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Removes dimensions of size 1 from the shape of a tensor.
tf.squeeze( input, axis=None, name=None ) Given a tensor input, this operation returns a tensor of the same type with all dimensions of size 1 removed. If you don't want to remove all size 1 dimensions, you can remove specific size 1 dimensions by specifying axis.
For example:
# 't' is a tensor of shape [1, 2, 1, 3, 1, 1] tf.shape(tf.squeeze(t)) # [2, 3] Or, to remove specific size 1 dimensions:
# 't' is a tensor of shape [1, 2, 1, 3, 1, 1] tf.shape(tf.squeeze(t, [2, 4])) # [1, 2, 3, 1] Unlike the older op tf.compat.v1.squeeze, this op does not accept a deprecated squeeze_dims argument.
@tf.function def func(x): print('x.shape:', x.shape) known_axes = [i for i, size in enumerate(x.shape) if size == 1] y = tf.squeeze(x, axis=known_axes) print('shape of tf.squeeze(x, axis=known_axes):', y.shape) y = tf.squeeze(x) print('shape of tf.squeeze(x):', y.shape) return 0 _ = func.get_concrete_function(tf.TensorSpec([None, 1, 2], dtype=tf.int32)) # Output is. # x.shape: (None, 1, 2) # shape of tf.squeeze(x, axis=known_axes): (None, 2) # shape of tf.squeeze(x): <unknown> Returns | |
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A Tensor. Has the same type as input. Contains the same data as input, but has one or more dimensions of size 1 removed. |
Raises | |
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ValueError | The input cannot be converted to a tensor, or the specified axis cannot be squeezed. |
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