Vector listIterator() method in Java with Examples

Last Updated : 02 Jan, 2019

java.util.Vector.listIterator()

This method returns a list iterator over the elements of a Vector object in proper sequence. It is bidirectional, so both forward and backward traversal is possible, using next() and previous() respectively. The iterator thus returned is fail-fast. This means that structurally modifying the vector after the iterator is created, in any way except through the iterator’s own remove or add methods (using Vector.add(), for example), will cause iterator to throw ConcurrentModificationException.

Syntax:

  public ListIterator listIterator()

Parameters: This method accepts no input arguments.

Return Value: This method returns a ListIterator object which can be used to traverse the Vector object.

Example 1: To demonstrate forward and backward traversal using listIterator().

   // Java code to illustrate listIterator() 
  
import java.util.Vector; 
import java.util.ListIterator; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
        // Declare empty vector 
        Vector<String> vt = new Vector<String>(); 
  
        vt.add("Geeks"); 
        vt.add("for"); 
        vt.add("Geeks"); 
        vt.add("2019"); 
        vt.add("AComputerSciencePortalForGeeks"); 
  
        // Declare list iterator 
        ListIterator listItr = vt.listIterator(); 
  
        // Forward iterations 
        System.out.println("Forward Traversal:"); 
        while (listItr.hasNext()) { 
            System.out.println(listItr.next()); 
        } 
  
        // Backward iterations 
        System.out.println("\nBackward Traversal:"); 
        while (listItr.hasPrevious()) { 
            System.out.println(listItr.previous()); 
        } 
    } 
} 
 
  

Output:

  Forward Traversal:  Geeks  for  Geeks  2019  AComputerSciencePortalForGeeks    Backward Traversal:  AComputerSciencePortalForGeeks  2019  Geeks  for  Geeks

java.util.Vector.listIterator(int index)

This method is used to return a list iterator by specifying starting index. Also bidirectional and fail-fast.

Syntax:

  public ListIterator listIterator(int index)

Parameters: The parameter index is an integer type value that specifies the first element to be returned from the list iterator (by a call to next()).

Return Value: This method returns a ListIterator object which can be used to traverse the Vector object.

Exception: This method throws IndexOutOfBoundsException, if the index is out of range (index < 0 or index > size())

Example 2: To demonstrate listIterator(int index).

   // Java code to illustrate listIterator(int index) 
  
import java.util.Vector; 
import java.util.ListIterator; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
        // Declare empty vector 
        Vector<String> vt = new Vector<String>(); 
  
        vt.add("Geeks"); 
        vt.add("for"); 
        vt.add("Geeks"); 
  
        // Declare list iterator 
        ListIterator listItr = vt.listIterator(1); 
        // traversal 
        while (listItr.hasNext()) { 
            System.out.println(listItr.next()); 
        } 
    } 
} 
 
  

Output:

  for  Geeks

Example 3: To demonstrate IndexOutOfBoundsException thrown by listIterator(int index).

   // Java code to illustrate IndexOutOfBoundsException 
// thrown by listIterator(int index) 
  
import java.util.Vector; 
import java.util.ListIterator; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
        // Declare empty vector 
        Vector<String> vt 
            = new Vector<String>(); 
  
        vt.add("Geeks"); 
        vt.add("for"); 
        vt.add("Geeks"); 
  
        // Declare list iterator at starting 
        // index greater than vector size 
        try { 
            ListIterator listItr 
                = vt.listIterator(5); 
        } 
        catch (IndexOutOfBoundsException e) { 
            // Exception handling 
            System.out.println("Exception: " + e); 
        } 
    } 
} 
 
  

Output:

  Exception: java.lang.IndexOutOfBoundsException: Index: 5

Example 4: To demonstrate ConcurrentModificationException thrown by ListIterator object when Vector object is modified after creating list iterator to it.

   // Java code to illustrate ConcurrentModificationException 
// thrown by ListIterator object 
  
import java.util.ConcurrentModificationException; 
import java.util.Vector; 
import java.util.ListIterator; 
  
public class GFG { 
    public static void main(String[] args) 
    { 
        // Declare empty vector 
        Vector<String> vt = new Vector<String>(); 
  
        vt.add("Geeks"); 
        vt.add("for"); 
  
        // Declare list iterator 
        ListIterator listItr = vt.listIterator(); 
  
        // modify vector after creating list iterator 
        vt.add("Geeks"); 
  
        try { 
            // Exception thrown here 
            System.out.println(listItr.next()); 
        } 
        catch (ConcurrentModificationException e) { 
            // Exception handling 
            System.out.println("Exception: " + e); 
        } 
    } 
} 
 
  

Output:

  Exception: java.util.ConcurrentModificationException

Reference:
https://docs.oracle.com/javase/8/docs/api/java/util/Vector.html#listIterator–

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Vector listIterator() method in Java with Examples

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