Variable Arguments (Varargs) in Java
Last Updated : 23 May, 2025
In Java, Variable Arguments (Varargs) write methods that can take any number of inputs, which simply means we do not have to create more methods for different numbers of parameters. This concept was introduced in Java 5 to make coding easier. Instead of passing arrays or multiple methods, we can simply use one method, and it will handle all the test cases.
Example: Now, let us see the demonstration of using Varargs in Java to pass a variable number of arguments to a method.
Java // Java program to pass a variable // number of arguments to a method import java.io.*; class Geeks { // Method that accepts variable number // of String arguments using varargs public static void Names(String... n) { // Iterate through the array // and print each name for (String i : n) { System.out.print(i + " "); } System.out.println(); } public static void main(String[] args) { // Calling the 'Names' method with // different number of arguments Names("geek1", "geek2"); Names("geek1", "geek2", "geek3"); } } Outputgeek1 geek2 geek1 geek2 geek3
Explanation: In the above example, the String... names allows the method to accept a variable number of String arguments. Inside the method, the for-each loop iterates over the names array and prints each name. The method is called twice in main(), with two and three arguments respectively.
What is Varargs?
Varargs lets a method to take many values or even no value at all. Java will treat these values like a list, so that we can use them inside the method easily.
Syntax of Varargs
Internally, the Varargs method is implemented by using the single dimensions arrays concept. Hence, in the Varargs method, we can differentiate arguments by using Index. A variable-length argument is specified by three periods or dots(…).
public static void fun(int ... a)
{
// method body
}
This syntax tells the compiler that fun( ) can be called with zero or more arguments. As a result, here, a is implicitly declared as an array of type int[].
Why do we Need Varargs?
- Until JDK 4, we can not declare a method with variable no. of arguments. If there is any change in the number of arguments, we have to declare a new method. This approach increases the length of the code and reduces readability.
- Before JDK 5, variable-length arguments could be handled in two ways.
- One uses an overloaded method(one for each).
- Another puts the arguments into an array and then passes this array to the method. Both of them are potentially error-prone and require more code.
- To resolve these problems, Variable Arguments (Varargs) were introduced in JDK 5. From JDK 5 onwards, we can declare a method with a variable number of arguments. Such types of methods are called Varargs methods. The varargs feature offers a simpler, better option.
Example: Varargs with Integer Arguments
Java // Demonstrating the working of // varargs with integer argument class Geeks { // A method that takes variable // number of integer arguments. static void fun(int... a) { System.out.println("Number of arguments: " + a.length); // using for each loop to display contents of a for (int i : a) System.out.print(i + " "); System.out.println(); } // Driver code public static void main(String args[]) { // Calling the varargs method with // one parameter fun(100); // four parameters fun(1, 2, 3, 4); // no parameter fun(); } } OutputNumber of arguments: 1 100 Number of arguments: 4 1 2 3 4 Number of arguments: 0
Explanation: In the above example, the fun(int... a) method accepts a variable number of integers. The length of the arguments is accessed using a.length. A for-each loop is used to iterate over the arguments and print each value.
Note: A method can have variable length parameters with other parameters too, but one should ensure that there exists only one varargs parameter that should be written last in the parameter list of the method declaration. For example:
int nums(int a, float b, double … c)
In this case, the first two arguments are matched with the first two parameters, and the remaining arguments belong to c.
Example: Varargs with Other Arguments
Java // Demonstrating the working of // varargs with other parameters class Geeks{ // Takes string as a argument // followed by varargs static void fun2(String s, int... a) { System.out.println("String: " + s); System.out.println("Number of arguments is: " + a.length); // using for each loop to // display contents of a for (int i : a) System.out.print(i + " "); System.out.println(); } public static void main(String args[]) { // Calling fun2() with different parameter fun2("GeeksforGeeks", 100, 200); fun2("CSPortal", 1, 2, 3, 4, 5); fun2("forGeeks"); } } OutputString: GeeksforGeeks Number of arguments is: 2 100 200 String: CSPortal Number of arguments is: 5 1 2 3 4 5 String: forGeeks Number of arguments is: 0
Important Rules and Limitations
Case 1: Specifying two Varargs in a single method:
void method(String... gfg, int... q)
{
// Compile time error as there
// are two varargs
}
Note: Only one Varargs parameter is allowed per method.
Case 2: Specifying Varargs as the first parameter of the method instead of the last one:
void method(int... gfg, String q)
{
// Compile time error as vararg
// appear before normal argument
}
Note: The Varargs parameter must be the last in the parameter list.
Important Points:
- Vararg Methods can also be overloaded, but overloading may lead to ambiguity.
- Vararg internally use an array to store arguments.
- Before JDK 5, variable length arguments could be handled in two ways: One was using overloading, other was using array argument.
- There can be only one variable argument in a method.
- Variable argument (Varargs) must be the last argument.