String Guide for Competitive Programming
Last Updated : 12 May, 2024
Strings are a sequence of characters, and are one of the most fundamental data structures in Competitive Programming. String problems are very common in competitive programming contests, and can range from simple to very challenging. In this article we are going to discuss about most frequent string tips and tricks that will help a programmer during Competitive Programming.
Common Operations on String:
1. Taking Strings as Input:
C++ #include <iostream> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(NULL); string word, sentence; // Input a single word cout<<"Enter a word: "; cin >> word; cout<<endl; // Input a line (multiple words) cin.ignore(); cout<<"Enter a sentence: "; getline(cin, sentence); cout<<endl; cout << "word = " << word << "\n"; cout << "sentence = " << sentence << "\n"; return 0; }
Java import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); // Prompt the user to enter a single word System.out.print("Enter a word: "); String word = scanner.next(); // Prompt the user to enter a sentence System.out.print("Enter a sentence: "); scanner.nextLine(); // consume the newline character left after reading the word String sentence = scanner.nextLine(); System.out.println("\nEntered word: " + word); System.out.println("Entered sentence: " + sentence); scanner.close(); } }
Python # Python code to read a word and a sentence from the user def main(): # Prompt the user to enter a single word word = input("Enter a word: ") # Prompt the user to enter a sentence sentence = input("Enter a sentence: ") # Display the entered word and sentence print("\nEntered word:", word) print("Entered sentence:", sentence) if __name__ == "__main__": main()
C# using System; class Program { static void Main() { string word, sentence; // Input a single word word = Console.ReadLine(); // Input a line (multiple words) sentence = Console.ReadLine(); Console.WriteLine($"word = {word}"); Console.WriteLine($"sentence = {sentence}"); } }
JavaScript let word, sentence; // Input a single word word = prompt("Enter a single word:"); // Input a sentence (multiple words) sentence = prompt("Enter a sentence:"); // Display the input console.log("word = " + word); console.log("sentence = " + sentence); //This code is contributed by Prachi.
OutputEnter a word: Enter a sentence: word = sentence =
2. Find the First and Last Occurrence of a Character in the String:
C++ #include <bits/stdc++.h> using namespace std; int main() { string str = "Learn Competitive Programming with GFG!"; size_t first = str.find('m'), last = str.find_last_of('m'); if (first != string::npos) cout << "First occurrence of m is at index = " << first << "\n"; if (last != string::npos) cout << "Last Occurrence of m is at index = " << last << "\n"; return 0; }
Java import java.io.*; class GFG { public static void main(String[] args) { String str = "Learn Competitive Programming with GFG!"; int first = str.indexOf('m'), last = str.lastIndexOf('m'); if (first != -1) System.out.println( "First Occurrence of m is at index = " + first); if (last != -1) System.out.println( "Last Occurrence of m is at index = " + last); } }
Python str = "Learn Competitive Programming with GFG!" first = str.find('m') last = str.rfind('m') if first != -1: print(f"First Occurrence of m is at index = {first}") if last != -1: print(f"Last Occurrence of m is at index = {last}")
C# using System; class Program { static void Main() { string str = "Learn Competitive Programming with GFG!"; int first = str.IndexOf('m'); int last = str.LastIndexOf('m'); if (first != -1) Console.WriteLine($"First occurrence of 'm' is at index = {first}"); if (last != -1) Console.WriteLine($"Last occurrence of 'm' is at index = {last}"); } }
JavaScript let str = "Learn Competitive Programming with GFG!"; let first = str.indexOf('m'); let last = str.lastIndexOf('m'); if (first !== -1) { console.log(`First Occurrence of m is at index = ${first}`); } if (last !== -1) { console.log(`Last Occurrence of m is at index = ${last}`); }
OutputFirst occurrence of m is at index = 8 Last Occurrence of m is at index = 25
3. Reverse a String:
C++ #include <bits/stdc++.h> using namespace std; int main() { string str = "Learn Competitive Programming with GFG!"; string rev(str.rbegin(), str.rend()); cout << "Reverse = " << rev << "\n"; return 0; }
Java import java.io.*; class GFG { public static void main(String[] args) { String str = "Learn Competitive Programming with GFG!"; StringBuilder rev = new StringBuilder(); rev.append(str); rev.reverse(); System.out.println("Reverse = " + rev); } }
Python str = "Learn Competitive Programming with GFG!" print(f"Reverse = {str[::-1]}")
C# using System; using System.Text; class Program { static void Main() { string str = "Learn Competitive Programming with GFG!"; string reversed = ReverseString(str); Console.WriteLine("Reverse = " + reversed); } static string ReverseString(string input) { char[] charArray = input.ToCharArray(); Array.Reverse(charArray); return new string(charArray); } }
JavaScript // Declare a string variable let str = "Learn Competitive Programming with GFG!"; // Reverse the string by converting it to an array of characters, reversing the array, and joining it back into a string let rev = str.split('').reverse().join(''); // Display the reversed string console.log("Reverse = " + rev);
OutputReverse = !GFG htiw gnimmargorP evititepmoC nraeL
4. Append a character/string at the end of the String:
C++ #include <bits/stdc++.h> using namespace std; int main() { string str = "Learn Competitive Programming with "; str.append("GFG!"); cout << "New String = " << str << "\n"; return 0; }
Java import java.io.*; class GFG { public static void main (String[] args) { StringBuilder str = new StringBuilder("Learn Competitive Programming with "); str.append("GFG!"); System.out.println("New String = " + str); } }
Python str = "Learn Competitive Programming with " str += "GFG!" print("New String = " + str)
C# using System; class MainClass { public static void Main(string[] args) { string str = "Learn Competitive Programming with "; str += "GFG!"; Console.WriteLine("New String = " + str); } } // this coe is contributed by utkarsh
JavaScript // Initialize a string variable let str = "Learn Competitive Programming with "; // Concatenate another string to the existing one using the += operator str += "GFG!"; // Display the updated string console.log("New String = " + str);
OutputNew String = Learn Competitive Programming with GFG!
5. Sorting a string:
C++ #include <bits/stdc++.h> using namespace std; int main() { string str = "Learn Competitive Programming with GFG!"; sort(str.begin(), str.end()); cout << "Sorted String = " << str << "\n"; return 0; }
Java /*package whatever //do not write package name here */ import java.util.*; class GFG { public static void main(String[] args) { String str = "Learn Competitive Programming with GFG!"; char array[] = str.toCharArray(); Arrays.sort(array); str = new String(array); System.out.println("Sorted String = " + str); } }
Python str = "Learn Competitive Programming with GFG!" str = "".join(sorted(str)) print(f"Sorted string = {str}")
C# using System; class MainClass { public static void Main(string[] args) { string str = "Learn Competitive Programming with GFG!"; // Convert the string to a char array, sort, and then convert back to string char[] charArray = str.ToCharArray(); Array.Sort(charArray); string sortedStr = new string(charArray); Console.WriteLine("Sorted String = " + sortedStr); // Alternatively, using LINQ //string sortedStr = new string(str.OrderBy(c => c).ToArray()); //Console.WriteLine("Sorted String = " + sortedStr); } }
JavaScript let str = "Learn Competitive Programming with GFG!"; let sortedStr = str.split('').sort().join(''); console.log("Sorted String =", sortedStr);
OutputSorted String = !CFGGLPaaeeegghiiiimmmnnooprrrtttvw
6. Substring extraction:
C++ #include <bits/stdc++.h> using namespace std; int main() { string str = "Learn Competitive Programming with GFG!"; cout << "Substring from index 6 to 16 = " << str.substr(6, 11) << "\n"; return 0; }
Java public class Main { public static void main(String[] args) { String str = "Learn Competitive Programming with GFG!"; String sub = str.substring(6, 17); // Index 6 to 16 System.out.println("Substring from index 6 to 16 = " + sub); } }
Python str = "Learn Competitive Programming with GFG!" substring = str[6:17] # Index 6 to 16 print("Substring from index 6 to 16 =", substring)
C# using System; class MainClass { public static void Main (string[] args) { // Initialize a string string str = "Learn Competitive Programming with GFG!"; // Extract substring from index 6 to 16 (11 characters) string substring = str.Substring(6, 11); // Display the extracted substring Console.WriteLine("Substring from index 6 to 16 = " + substring); } }
JavaScript // Main function function main() { // Define the string const str = "Learn Competitive Programming with GFG!"; // Extract substring from index 6 to 16 const substring = str.substring(6, 17); // Print the extracted substring console.log("Substring from index 6 to 16 =", substring); } // Call the main function to execute the program main();
OutputSubstring from index 6 to 16 = Competitive
Competitive Programming Tips for Strings in C++:
1. Pass by reference:
We should always pass the reference of strings to avoid making copies of the original string which is quite inefficient.
C++ #include <iostream> using namespace std; // Pass by value int countSpaceSlow(string str, int idx) { if (idx == str.length()) return 0; return countSpaceSlow(str, idx + 1) + (str[idx] == ' ' ? 1 : 0); } // Pass by reference int countSpaceFast(string& str, int idx) { if (idx == str.length()) return 0; return countSpaceSlow(str, idx + 1) + (str[idx] == ' ' ? 1 : 0); } int main() { string str = "Learn Competitive programming with GFG!"; cout << countSpaceSlow(str, 0) << "\n"; cout << countSpaceFast(str, 0) << "\n"; return 0; }
Java public class Main { // Pass by value public static int countSpaceSlow(String str, int idx) { if (idx == str.length()) return 0; return countSpaceSlow(str, idx + 1) + (str.charAt(idx) == ' ' ? 1 : 0); } // Pass by reference (Java doesn't have true pass-by-reference, but we can use mutable objects like StringBuilder) public static int countSpaceFast(StringBuilder str, int idx) { if (idx == str.length()) return 0; return countSpaceSlow(str.toString(), idx + 1) + (str.charAt(idx) == ' ' ? 1 : 0); } public static void main(String[] args) { String str = "Learn Competitive programming with GFG!"; System.out.println(countSpaceSlow(str, 0)); System.out.println(countSpaceFast(new StringBuilder(str), 0)); } } //This code is contributed by Monu.
Python # Pass by value def count_space_slow(string, idx): if idx == len(string): return 0 return count_space_slow(string, idx + 1) + (string[idx] == ' ') # Pass by reference (using a list) def count_space_fast(string, idx): if idx == len(string): return 0 return count_space_slow(string, idx + 1) + (string[idx] == ' ') if __name__ == "__main__": string = list("Learn Competitive programming with GFG!") print(count_space_slow(string, 0)) print(count_space_fast(string, 0))
JavaScript // Pass by value function countSpaceSlow(str, idx) { if (idx === str.length) return 0; return countSpaceSlow(str, idx + 1) + (str[idx] === ' ' ? 1 : 0); } // Pass by reference (not applicable in JavaScript) // Just for the sake of consistency, we'll keep the function signature function countSpaceFast(str, idx) { if (idx === str.length) return 0; return countSpaceSlow(str, idx + 1) + (str[idx] === ' ' ? 1 : 0); } let str = "Learn Competitive programming with GFG!"; console.log(countSpaceSlow(str, 0)); console.log(countSpaceFast(str, 0)); // No pass by reference in JavaScript, so same as countSpaceSlow
2. push_back() vs + operator:
We should always use push_back() function instead of + operator, to add a character at the end of the string. This is because the time complexity of + operator depends on the length of the string O(N) whereas push_back() simply pushes the character at the end in O(1) time complexity. So, if we need to append characters in a loop, push_back() will have much better performance as compared to + operator.
C++ #include <iostream> using namespace std; // Slow because of + operator string filterLowerCaseSlow(string str) { string res = ""; for (int i = 0; i < str.length(); i++) { if (str[i] >= 'a' && str[i] <= 'z') res += str[i]; } return res; } // Fast because of push_back() string filterLowerCaseFast(string& str) { string res = ""; for (int i = 0; i < str.length(); i++) { if (str[i] >= 'a' && str[i] <= 'z') res.push_back(str[i]); } return res; } int main() { string str = "Learn Competitive programming with GFG!"; cout << filterLowerCaseSlow(str) << "\n"; cout << filterLowerCaseFast(str) << "\n"; return 0; }
Java public class Main { // Slow because of concatenating strings using '+' public static String filterLowerCaseSlow(String str) { String res = ""; for (int i = 0; i < str.length(); i++) { if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z') res += str.charAt(i); } return res; } // Fast because of using StringBuilder's append() method public static String filterLowerCaseFast(String str) { StringBuilder res = new StringBuilder(); for (int i = 0; i < str.length(); i++) { if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z') res.append(str.charAt(i)); } return res.toString(); } public static void main(String[] args) { String str = "Learn Competitive programming with GFG!"; System.out.println(filterLowerCaseSlow(str)); System.out.println(filterLowerCaseFast(str)); } }
Python class Main: @staticmethod # Slow because of concatenating strings using '+' def filter_lower_case_slow(string): res = "" for char in string: if 'a' <= char <= 'z': res += char return res @staticmethod # Fast because of using StringBuilder's append() method def filter_lower_case_fast(string): res = [] for char in string: if 'a' <= char <= 'z': res.append(char) return ''.join(res) @staticmethod def main(): string = "Learn Competitive programming with GFG!" print(Main.filter_lower_case_slow(string)) print(Main.filter_lower_case_fast(string)) # Call the main function to execute the program Main.main()
JavaScript // Slow because of concatenating strings using '+' function filterLowerCaseSlow(str) { let res = ""; for (let i = 0; i < str.length; i++) { if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z') res += str.charAt(i); } return res; } // Fast because of using StringBuilder's append() method function filterLowerCaseFast(str) { let res = ''; for (let i = 0; i < str.length; i++) { if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z') res += str.charAt(i); } return res; } const str = "Learn Competitive programming with GFG!"; console.log(filterLowerCaseSlow(str)); console.log(filterLowerCaseFast(str));
Outputearnompetitiveprogrammingwith earnompetitiveprogrammingwith
Competitive Programming Tips for Strings in Java:
1. StringBuilder vs + operator:
Avoid using the + operator repeatedly when concatenating multiple strings. This can create unnecessary string objects, leading to poor performance. Instead, use StringBuilder (or StringBuffer for thread safety) to efficiently concatenate strings.
Java import java.io.*; class GFG { public static void main(String[] args) { // Slow Concatenation of Strings String str1 = ""; str1 = str1 + "Hello"; str1 = str1 + " "; str1 = str1 + "World"; System.out.println(str1); // Fast Concatenation of Strings StringBuilder str2 = new StringBuilder(); str2.append("Hello"); str2.append(" "); str2.append("World"); System.out.println(str2); } }
Python class GFG: def __init__(self): pass def main(self): # Slow Concatenation of Strings str1 = "" str1 += "Hello" str1 += " " str1 += "World" print(str1) # Fast Concatenation of Strings str2 = [] str2.append("Hello") str2.append(" ") str2.append("World") print("".join(str2)) # Creating an instance of the class and calling the main method gfg = GFG() gfg.main()
OutputHello World Hello World
2. Use the equals() Method for String Comparison:
When comparing string content, use the equals() method or its variants (equalsIgnoreCase(), startsWith(), endsWith(), etc.) instead of the “==” operator, which compares object references.
Java import java.io.*; class GFG { public static void main(String[] args) { String s1 = "GFG", s2 = "GFG"; // Incorrect implementation System.out.println(s1 == s2); System.out.println(new String("GFG") == new String("GFG")); // Correct Implementation System.out.println(s1.equals(s2)); System.out.println( new String("GFG").equals(new String("GFG"))); } }
Outputtrue false true true
Competitive Programming Tips for Strings in Python:
1. Use String Slicing and Concatenation Effectively.
String slicing is a powerful way to extract substrings from a string. You can use slicing to get individual characters, substrings of any length, or even reversed strings. String concatenation is used to join two or more strings together. There are two ways to concatenate strings in Python: using the +
operator or the join()
method. The +
operator is more efficient for concatenating a small number of strings, while the join()
method is more efficient for concatenating a large number of strings.
Python Str = "Learn Competitive Programming " print(f"First five characters = {Str[0:5]}") print(f"Reverse = {Str[::-1]}") Str += "with " Str = "".join([Str, "GFG!"]) print(Str)
OutputFirst five characters = Learn Reverse = gnimmargorP evititepmoC nraeL Learn Competitive Programming with GFG!
2. Use Regular Expressions for Pattern Matching:
Regular expressions are a powerful tool for matching patterns in strings. Python has a built-in re
module that provides regular expression support.
Python import re # Method to find the number of words using Regex def count_words(text): words = re.findall(r"\w+", text) return len(words) print(count_words("Learn Competitive Programming with GFG!"))
Important String Algorithms for Competitive Programming:
Here are some important string algorithms for competitive programming:
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