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Fast I/O for Competitive Programming
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String Guide for Competitive Programming

Last Updated : 12 May, 2024
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Strings are a sequence of characters, and are one of the most fundamental data structures in Competitive Programming. String problems are very common in competitive programming contests, and can range from simple to very challenging. In this article we are going to discuss about most frequent string tips and tricks that will help a programmer during Competitive Programming.

Table of Content

  • Common Operations on String
  • Competitive Programming Tips for Strings in C++
  • Competitive Programming Tips for Strings in Java
  • Competitive Programming Tips for Strings in Python
  • Important String Algorithms for Competitive Programming

Common Operations on String:

1. Taking Strings as Input:

C++
#include <iostream> using namespace std;  int main() {      ios_base::sync_with_stdio(false);     cin.tie(NULL);      string word, sentence;     // Input a single word      cout<<"Enter a word: ";     cin >> word;     cout<<endl;     // Input a line (multiple words)      cin.ignore();     cout<<"Enter a sentence: ";     getline(cin, sentence);     cout<<endl;        cout << "word = " << word << "\n";     cout << "sentence = " << sentence << "\n";          return 0; } 
Java
import java.util.Scanner;  public class Main {     public static void main(String[] args) {         Scanner scanner = new Scanner(System.in);          // Prompt the user to enter a single word         System.out.print("Enter a word: ");         String word = scanner.next();          // Prompt the user to enter a sentence         System.out.print("Enter a sentence: ");         scanner.nextLine(); // consume the newline character left after reading the word         String sentence = scanner.nextLine();          System.out.println("\nEntered word: " + word);         System.out.println("Entered sentence: " + sentence);          scanner.close();     } } 
Python
# Python code to read a word and a sentence from the user  def main():     # Prompt the user to enter a single word     word = input("Enter a word: ")      # Prompt the user to enter a sentence     sentence = input("Enter a sentence: ")      # Display the entered word and sentence     print("\nEntered word:", word)     print("Entered sentence:", sentence)  if __name__ == "__main__":     main() 
C#
using System;  class Program {     static void Main()     {         string word, sentence;          // Input a single word         word = Console.ReadLine();          // Input a line (multiple words)         sentence = Console.ReadLine();          Console.WriteLine($"word = {word}");         Console.WriteLine($"sentence = {sentence}");     } } 
JavaScript
let word, sentence;  // Input a single word word = prompt("Enter a single word:");  // Input a sentence (multiple words) sentence = prompt("Enter a sentence:");  // Display the input console.log("word = " + word); console.log("sentence = " + sentence); //This code is contributed by Prachi. 

Output
Enter a word:  Enter a sentence:  word =  sentence =  

2. Find the First and Last Occurrence of a Character in the String:

C++
#include <bits/stdc++.h> using namespace std;  int main() {      string str = "Learn Competitive Programming with GFG!";     size_t first = str.find('m'),         last = str.find_last_of('m');     if (first != string::npos)         cout << "First occurrence of m is at index = "             << first << "\n";     if (last != string::npos)         cout << "Last Occurrence of m is at index = "             << last << "\n";     return 0; } 
Java
import java.io.*;  class GFG {     public static void main(String[] args)     {         String str = "Learn Competitive Programming with GFG!";         int first = str.indexOf('m'),             last = str.lastIndexOf('m');         if (first != -1)             System.out.println(                 "First Occurrence of m is at index = "                 + first);         if (last != -1)             System.out.println(                 "Last Occurrence of m is at index = "                 + last);     } } 
Python
str = "Learn Competitive Programming with GFG!" first = str.find('m') last = str.rfind('m') if first != -1:     print(f"First Occurrence of m is at index = {first}") if last != -1:     print(f"Last Occurrence of m is at index = {last}") 
C#
using System;  class Program {     static void Main()     {         string str = "Learn Competitive Programming with GFG!";          int first = str.IndexOf('m');         int last = str.LastIndexOf('m');          if (first != -1)             Console.WriteLine($"First occurrence of 'm' is at index = {first}");                  if (last != -1)             Console.WriteLine($"Last occurrence of 'm' is at index = {last}");                      } } 
JavaScript
let str = "Learn Competitive Programming with GFG!"; let first = str.indexOf('m'); let last = str.lastIndexOf('m');  if (first !== -1) {     console.log(`First Occurrence of m is at index = ${first}`); }  if (last !== -1) {     console.log(`Last Occurrence of m is at index = ${last}`); } 

Output
First occurrence of m is at index = 8 Last Occurrence of m is at index = 25 

3. Reverse a String:

C++
#include <bits/stdc++.h> using namespace std;  int main() {     string str = "Learn Competitive Programming with GFG!";     string rev(str.rbegin(), str.rend());     cout << "Reverse = " << rev << "\n";     return 0; } 
Java
import java.io.*;  class GFG {     public static void main(String[] args)     {         String str = "Learn Competitive Programming with GFG!";         StringBuilder rev = new StringBuilder();         rev.append(str);         rev.reverse();         System.out.println("Reverse = " + rev);     } } 
Python
str = "Learn Competitive Programming with GFG!" print(f"Reverse = {str[::-1]}") 
C#
using System; using System.Text;  class Program {     static void Main()     {         string str = "Learn Competitive Programming with GFG!";         string reversed = ReverseString(str);                  Console.WriteLine("Reverse = " + reversed);     }      static string ReverseString(string input)     {         char[] charArray = input.ToCharArray();         Array.Reverse(charArray);         return new string(charArray);     } } 
JavaScript
// Declare a string variable let str = "Learn Competitive Programming with GFG!";  // Reverse the string by converting it to an array of characters, reversing the array, and joining it back into a string let rev = str.split('').reverse().join('');  // Display the reversed string console.log("Reverse = " + rev); 

Output
Reverse = !GFG htiw gnimmargorP evititepmoC nraeL 

4. Append a character/string at the end of the String:

C++
#include <bits/stdc++.h> using namespace std;  int main() {     string str = "Learn Competitive Programming with ";     str.append("GFG!");     cout << "New String = " << str << "\n";     return 0; } 
Java
import java.io.*;  class GFG {     public static void main (String[] args) {         StringBuilder str = new StringBuilder("Learn Competitive Programming with ");         str.append("GFG!");         System.out.println("New String = " + str);     } } 
Python
str = "Learn Competitive Programming with " str += "GFG!" print("New String = " + str) 
C#
using System;  class MainClass {     public static void Main(string[] args) {         string str = "Learn Competitive Programming with ";         str += "GFG!";         Console.WriteLine("New String = " + str);     } } // this coe is contributed by utkarsh 
JavaScript
// Initialize a string variable let str = "Learn Competitive Programming with ";  // Concatenate another string to the existing one using the += operator str += "GFG!";  // Display the updated string console.log("New String = " + str); 

Output
New String = Learn Competitive Programming with GFG! 

5. Sorting a string:

C++
#include <bits/stdc++.h> using namespace std;  int main() {     string str = "Learn Competitive Programming with GFG!";     sort(str.begin(), str.end());     cout << "Sorted String = " << str << "\n";      return 0; } 
Java
/*package whatever //do not write package name here */  import java.util.*;  class GFG {     public static void main(String[] args)     {         String str             = "Learn Competitive Programming with GFG!";         char array[] = str.toCharArray();         Arrays.sort(array);         str = new String(array);         System.out.println("Sorted String = " + str);     } } 
Python
str = "Learn Competitive Programming with GFG!" str = "".join(sorted(str)) print(f"Sorted string = {str}") 
C#
using System;  class MainClass {     public static void Main(string[] args)     {         string str = "Learn Competitive Programming with GFG!";                  // Convert the string to a char array, sort, and then convert back to string         char[] charArray = str.ToCharArray();         Array.Sort(charArray);         string sortedStr = new string(charArray);          Console.WriteLine("Sorted String = " + sortedStr);          // Alternatively, using LINQ         //string sortedStr = new string(str.OrderBy(c => c).ToArray());         //Console.WriteLine("Sorted String = " + sortedStr);     } } 
JavaScript
let str = "Learn Competitive Programming with GFG!"; let sortedStr = str.split('').sort().join(''); console.log("Sorted String =", sortedStr); 

Output
Sorted String =     !CFGGLPaaeeegghiiiimmmnnooprrrtttvw 

6. Substring extraction:

C++
#include <bits/stdc++.h> using namespace std;  int main() {     string str = "Learn Competitive Programming with GFG!";     cout << "Substring from index 6 to 16 = "         << str.substr(6, 11) << "\n";     return 0; } 
Java
public class Main {     public static void main(String[] args) {         String str = "Learn Competitive Programming with GFG!";         String sub = str.substring(6, 17); // Index 6 to 16         System.out.println("Substring from index 6 to 16 = " + sub);     } } 
Python
str = "Learn Competitive Programming with GFG!" substring = str[6:17]  # Index 6 to 16 print("Substring from index 6 to 16 =", substring) 
C#
using System;  class MainClass {     public static void Main (string[] args) {         // Initialize a string         string str = "Learn Competitive Programming with GFG!";                  // Extract substring from index 6 to 16 (11 characters)         string substring = str.Substring(6, 11);                  // Display the extracted substring         Console.WriteLine("Substring from index 6 to 16 = " + substring);     } } 
JavaScript
// Main function function main() {     // Define the string     const str = "Learn Competitive Programming with GFG!";          // Extract substring from index 6 to 16     const substring = str.substring(6, 17);      // Print the extracted substring     console.log("Substring from index 6 to 16 =", substring); }  // Call the main function to execute the program main(); 

Output
Substring from index 6 to 16 = Competitive 

Competitive Programming Tips for Strings in C++:

1. Pass by reference:

We should always pass the reference of strings to avoid making copies of the original string which is quite inefficient.

C++
#include <iostream> using namespace std;  // Pass by value int countSpaceSlow(string str, int idx) {     if (idx == str.length())         return 0;     return countSpaceSlow(str, idx + 1)         + (str[idx] == ' ' ? 1 : 0); }  // Pass by reference int countSpaceFast(string& str, int idx) {     if (idx == str.length())         return 0;     return countSpaceSlow(str, idx + 1)         + (str[idx] == ' ' ? 1 : 0); }  int main() {     string str = "Learn Competitive programming with GFG!";     cout << countSpaceSlow(str, 0) << "\n";     cout << countSpaceFast(str, 0) << "\n";     return 0; } 
Java
public class Main {     // Pass by value     public static int countSpaceSlow(String str, int idx) {         if (idx == str.length())             return 0;         return countSpaceSlow(str, idx + 1)                 + (str.charAt(idx) == ' ' ? 1 : 0);     }      // Pass by reference (Java doesn't have true pass-by-reference, but we can use mutable objects like StringBuilder)     public static int countSpaceFast(StringBuilder str, int idx) {         if (idx == str.length())             return 0;         return countSpaceSlow(str.toString(), idx + 1)                 + (str.charAt(idx) == ' ' ? 1 : 0);     }      public static void main(String[] args) {         String str = "Learn Competitive programming with GFG!";         System.out.println(countSpaceSlow(str, 0));         System.out.println(countSpaceFast(new StringBuilder(str), 0));     } } //This code is contributed by Monu. 
Python
# Pass by value def count_space_slow(string, idx):     if idx == len(string):         return 0     return count_space_slow(string, idx + 1) + (string[idx] == ' ')  # Pass by reference (using a list) def count_space_fast(string, idx):     if idx == len(string):         return 0     return count_space_slow(string, idx + 1) + (string[idx] == ' ')  if __name__ == "__main__":     string = list("Learn Competitive programming with GFG!")     print(count_space_slow(string, 0))     print(count_space_fast(string, 0)) 
JavaScript
// Pass by value function countSpaceSlow(str, idx) {     if (idx === str.length)         return 0;     return countSpaceSlow(str, idx + 1) + (str[idx] === ' ' ? 1 : 0); }  // Pass by reference (not applicable in JavaScript) // Just for the sake of consistency, we'll keep the function signature function countSpaceFast(str, idx) {     if (idx === str.length)         return 0;     return countSpaceSlow(str, idx + 1) + (str[idx] === ' ' ? 1 : 0); }  let str = "Learn Competitive programming with GFG!"; console.log(countSpaceSlow(str, 0)); console.log(countSpaceFast(str, 0)); // No pass by reference in JavaScript, so same as countSpaceSlow 

Output
4 4 

2. push_back() vs + operator:

We should always use push_back() function instead of + operator, to add a character at the end of the string. This is because the time complexity of + operator depends on the length of the string O(N) whereas push_back() simply pushes the character at the end in O(1) time complexity. So, if we need to append characters in a loop, push_back() will have much better performance as compared to + operator.

C++
#include <iostream> using namespace std;  // Slow because of + operator string filterLowerCaseSlow(string str) {     string res = "";     for (int i = 0; i < str.length(); i++) {         if (str[i] >= 'a' && str[i] <= 'z')             res += str[i];     }     return res; }  // Fast because of push_back() string filterLowerCaseFast(string& str) {     string res = "";     for (int i = 0; i < str.length(); i++) {         if (str[i] >= 'a' && str[i] <= 'z')             res.push_back(str[i]);     }     return res; }  int main() {     string str = "Learn Competitive programming with GFG!";     cout << filterLowerCaseSlow(str) << "\n";     cout << filterLowerCaseFast(str) << "\n";     return 0; } 
Java
public class Main {      // Slow because of concatenating strings using '+'     public static String filterLowerCaseSlow(String str) {         String res = "";         for (int i = 0; i < str.length(); i++) {             if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z')                 res += str.charAt(i);         }         return res;     }      // Fast because of using StringBuilder's append() method     public static String filterLowerCaseFast(String str) {         StringBuilder res = new StringBuilder();         for (int i = 0; i < str.length(); i++) {             if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z')                 res.append(str.charAt(i));         }         return res.toString();     }      public static void main(String[] args) {         String str = "Learn Competitive programming with GFG!";         System.out.println(filterLowerCaseSlow(str));         System.out.println(filterLowerCaseFast(str));     } } 
Python
class Main:     @staticmethod     # Slow because of concatenating strings using '+'     def filter_lower_case_slow(string):         res = ""         for char in string:             if 'a' <= char <= 'z':                 res += char         return res      @staticmethod     # Fast because of using StringBuilder's append() method     def filter_lower_case_fast(string):         res = []         for char in string:             if 'a' <= char <= 'z':                 res.append(char)         return ''.join(res)      @staticmethod     def main():         string = "Learn Competitive programming with GFG!"         print(Main.filter_lower_case_slow(string))         print(Main.filter_lower_case_fast(string))   # Call the main function to execute the program Main.main() 
JavaScript
// Slow because of concatenating strings using '+' function filterLowerCaseSlow(str) {     let res = "";     for (let i = 0; i < str.length; i++) {         if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z')             res += str.charAt(i);     }     return res; }  // Fast because of using StringBuilder's append() method function filterLowerCaseFast(str) {     let res = '';     for (let i = 0; i < str.length; i++) {         if (str.charAt(i) >= 'a' && str.charAt(i) <= 'z')             res += str.charAt(i);     }     return res; }  const str = "Learn Competitive programming with GFG!"; console.log(filterLowerCaseSlow(str)); console.log(filterLowerCaseFast(str)); 

Output
earnompetitiveprogrammingwith earnompetitiveprogrammingwith 

Competitive Programming Tips for Strings in Java:

1. StringBuilder vs + operator:

Avoid using the + operator repeatedly when concatenating multiple strings. This can create unnecessary string objects, leading to poor performance. Instead, use StringBuilder (or StringBuffer for thread safety) to efficiently concatenate strings.

Java
import java.io.*;  class GFG {     public static void main(String[] args)     {         // Slow Concatenation of Strings         String str1 = "";         str1 = str1 + "Hello";         str1 = str1 + " ";         str1 = str1 + "World";         System.out.println(str1);          // Fast Concatenation of Strings         StringBuilder str2 = new StringBuilder();         str2.append("Hello");         str2.append(" ");         str2.append("World");         System.out.println(str2);     } } 
Python
class GFG:     def __init__(self):         pass      def main(self):         # Slow Concatenation of Strings         str1 = ""         str1 += "Hello"         str1 += " "         str1 += "World"         print(str1)          # Fast Concatenation of Strings         str2 = []         str2.append("Hello")         str2.append(" ")         str2.append("World")         print("".join(str2))  # Creating an instance of the class and calling the main method gfg = GFG() gfg.main() 

Output
Hello World Hello World 

2. Use the equals() Method for String Comparison:

When comparing string content, use the equals() method or its variants (equalsIgnoreCase(), startsWith(), endsWith(), etc.) instead of the “==” operator, which compares object references.

Java
import java.io.*;  class GFG {     public static void main(String[] args)     {         String s1 = "GFG", s2 = "GFG";         // Incorrect implementation         System.out.println(s1 == s2);         System.out.println(new String("GFG")                            == new String("GFG"));          // Correct Implementation         System.out.println(s1.equals(s2));         System.out.println(             new String("GFG").equals(new String("GFG")));     } } 

Output
true false true true 

Competitive Programming Tips for Strings in Python:

1. Use String Slicing and Concatenation Effectively.

String slicing is a powerful way to extract substrings from a string. You can use slicing to get individual characters, substrings of any length, or even reversed strings. String concatenation is used to join two or more strings together. There are two ways to concatenate strings in Python: using the + operator or the join() method. The + operator is more efficient for concatenating a small number of strings, while the join() method is more efficient for concatenating a large number of strings.

Python
Str = "Learn Competitive Programming " print(f"First five characters = {Str[0:5]}") print(f"Reverse = {Str[::-1]}")  Str += "with " Str = "".join([Str, "GFG!"])  print(Str) 

Output
First five characters = Learn Reverse =  gnimmargorP evititepmoC nraeL Learn Competitive Programming with GFG! 

2. Use Regular Expressions for Pattern Matching:

Regular expressions are a powerful tool for matching patterns in strings. Python has a built-in re module that provides regular expression support.

Python
import re  # Method to find the number of words using Regex def count_words(text):     words = re.findall(r"\w+", text)     return len(words)  print(count_words("Learn Competitive Programming with GFG!")) 

Output
5 

Important String Algorithms for Competitive Programming:

Here are some important string algorithms for competitive programming:

String Algorithms

String hashing using Polynomial rolling hash function

Rabin-Karp Algorithm for Pattern Searching

KMP Algorithm for Pattern Searching

Z algorithm (Linear time pattern searching Algorithm)

Suffix Array Pattern Searching

Aho-Corasick Algorithm for Pattern Searching

Finite Automata algorithm for Pattern Searching

Boyer Moore Algorithm for Pattern Searching

Manacher’s Algorithm – Linear Time Longest Palindromic Substring



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