Python | Ways to split a string in different ways
Last Updated : 26 Feb, 2023
The most common problem we have encountered in Python is splitting a string by a delimiter, But in some cases we have to split in different ways to get the answer. In this article, we will get substrings obtained by splitting string in different ways. Examples:
Input : Paras_Jain_Moengage_best
Output : ['Paras', 'Paras_Jain', 'Paras_Jain_Moengage', 'Paras_Jain_Moengage_best']
Input : chunky_2808_GFG_Codechef
Output : ['chunky', 'chunky_2808', 'chunky_2808_GFG', 'chunky_2808_GFG_Codechef']
Below are some ways to do the task.
Method #1: Using Iteration
Python3 # Python code to split string in substring manner # Input initialisation Input = "Geeks_for_geeks_is_best" # Split initialise split_string = Input.split('_') # Output list initialise Output = [] # Iteration for a in range(len(split_string)): temp = split_string[:a + 1] temp = "_".join(temp) Output.append(temp) # print output print(Output) Output:['Geeks', 'Geeks_for', 'Geeks_for_geeks', 'Geeks_for_geeks_is', 'Geeks_for_geeks_is_best']
Time Complexity: O(n), where n is the length of the string.
Space Complexity: O(n), where n is the length of the string.
Method 2: Using Itertools
Python3 # Python code to split string in substring manner # Importing from itertools import accumulate # Input initialisation Input = "Geeks_for_geeks_is_best" # Using accumulate Output = [*accumulate(Input.split('_'), lambda temp1, temp2 : '_'.join([temp1, temp2])), ] # Printing output print(Output) Output:['Geeks', 'Geeks_for', 'Geeks_for_geeks', 'Geeks_for_geeks_is', 'Geeks_for_geeks_is_best']
Time complexity: O(n), where n is the length of the input string.
Auxiliary space: O(n), as we are creating a list to store the output of the accumulate function.
Method#3 : Using re module and string slicing
Python3 # Python code to split string in substring manner # Importing import re # Input initialisation Input = "Geeks_for_geeks_is_best" # Using re module with string slicing to generate substring ans = [] for i in re.finditer("(_)", Input): temp = Input[:i.span()[0]] ans.append(temp) # inserting last substring ans.append(Input) # Printing output print(ans) Output:
['Geeks', 'Geeks_for', 'Geeks_for_geeks', 'Geeks_for_geeks_is', 'Geeks_for_geeks_is_best']
Time complexity: O(n), where n is the length of the input string.
Auxiliary space: O(m), where m is the number of substrings generated.
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