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Python - Sort Dictionary key and values List

Python | Ways to sort a zipped list by values

Last Updated : 26 Dec, 2024

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Sorting a zipped list in Python refers to arranging pairs of elements, typically tuples, based on their values. This allows us to reorder the list according to the second item in each pair, while keeping the key-value relationship intact. In this article we’ll explore ways to sort a zipped list by values.

Using sorted() with operator.itemgetter()

operator.itemgetter() is a fast way to sort a zipped list by values. It efficiently retrieves specific elements from tuples, making it ideal for sorting large datasets.

Example:

Python

import operator a = ['akshat', 'Manjeet', 'nikhil'] b = [3, 2, 1] zipped = zip(a,b)  # Converting to list zipped = list(zipped)  # Using sorted and operator res = sorted(zipped, key = operator.itemgetter(1)) print(str(res))

Output

[('akshat', 3), ('Manjeet', 2), ('nikhil', 1)]

Explanation:

This code zips lists a and b into pairs.
It sorts the pairs by the second element .
Result is a list sorted by values in b in ascending order.

Let’s understand more ways to sort a zipped list by values .

Using sorted () with lambda

Lambda functions provide a flexible way to sort a zipped list by values, allowing custom sorting logic. This method is simple and useful for quick sorting tasks in Python.

Example:

Python

a = ['geeks', 'for', 'Geeks'] b= [3, 2, 1]  # Zipping the lists zipped = zip(a,b)  # Converting to list zipped = list(zipped)  # Sorting by second element res = sorted(zipped, key=lambda x: x[1],) print(res)

Output

[('Geeks', 1), ('for', 2), ('geeks', 3)]

Explanation:

This code zips lists a and b and sorts the pairs by the second element in ascending order using lambda function.

The sort() method sorts a zipped list in place, which means it modifies the list directly without creating a new one. While this is efficient for smaller datasets, it may be slower than using sorted() with operator.itemgetter() for larger datasets.

Example:

Python

a = ['geeks','for','Geeks'] b = [3, 2, 1]  # Zipping the lists zipped = zip(a, b)  # Converting to list zipped = list(zipped)  # Sorting in-place by second element zipped.sort(key=lambda x: x[1]) print(zipped)

Output

[('Geeks', 1), ('for', 2), ('geeks', 3)]

Explanation:

This code zips lists a and b into pairs of corresponding elements.
It sorts the pairs in-place by the second element in ascending order using lambda function.

Python - Sort Dictionary key and values List

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