Python program to find the most occurring character and its count
Last Updated : 15 Mar, 2023
Given a string, write a python program to find the most occurrence character and its number of occurrences. Examples:
Input : hello Output : ('l', 2) Input : geeksforgeeks Output : ('e', 4) We can solve this problem quickly in python using Counter() method. Simple Approach is to 1) Create a dictionary using Counter method having strings as keys and their frequencies as values. 2) Find the maximum occurrence of a character i.e. value and get the index of it.
Python # Python program to find the most occurring # character and its count from collections import Counter def find_most_occ_char(input): # now create dictionary using counter method # which will have strings as key and their # frequencies as value wc = Counter(input) # Finding maximum occurrence of a character # and get the index of it. s = max(wc.values()) i = wc.values().index(s) print wc.items()[i] # Driver program if __name__ == "__main__": input = 'geeksforgeeks' find_most_occ_char(input)
Output:
('e', 4) Time Complexity: O(N) where N is the length of the input string
Auxiliary Space: O(1)
One more approach to find the most occurring character and its count in python3
Python3 # python code to find most occurring character in a string and its count string1="geeksforgeeks" list1=[] list2=[] for i in string1: if i not in list1: list1.append(i)#appending unique characters of string list2.append(string1.count(i)) #finding maximum in the list occ=max(list2) ele=list1[list2.index(occ)] print(ele,occ)
Time Complexity: O(N)
Auxiliary Space: O(N)
Approach : Using operator.countOf() and index() methods
Python3 # python code to find most occurring character in a string and its count string1="geeksforgeeks" list1=[] list2=[] for i in string1: if i not in list1: list1.append(i)#appending unique characters of string import operator list2.append(operator.countOf(string1,i)) #finding maximum in the list occ=max(list2) ele=list1[list2.index(occ)] print(ele,occ)
Time Complexity: O(N)
Auxiliary Space: O(N)
Approach: Using lambda function
This new approach uses a lambda function to count the occurrences of each character in the string, and then creates a list of tuples containing the character and its count. Finally, it finds the tuple with the maximum count and prints its character and counts.
Python3 # python code to find most occurring character in a string and its count string1 = "geeksforgeeks" # use a lambda function to count occurrences of each character in the string count_char = lambda c: string1.count(c) # create a list of tuples containing the character and its count char_counts = [(c, count_char(c)) for c in set(string1)] # find the tuple with the maximum count and print its character and count most_common = max(char_counts, key=lambda x: x[1]) print(most_common[0], most_common[1]) # Contributed by adityasha4x71
Time Complexity: O(N*N), due to count() function used in the lambda
Auxiliary Space: O(N), for creating a list of tuples containing the character and its count.
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