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Python Program to Check Number is a Power of Two

Python Program to Check if a Number is Odd or Even

Last Updated : 27 Nov, 2024

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Even Numbers are exactly divisible by 2 and Odd Numbers are not exactly divisible by 2. We can use modulo operator (%) to check if the number is even or odd. For even numbers, the remainder when divided by 2 is 0, and for odd numbers, the remainder is 1.

In this article, we will learn how to check if given number is Even or Odd using Python.

Python

x = 24  # Check the remainder dividing x by 2 is 0 if x % 2 == 0:     print("Even") else:     print("Odd")  # Checking another number     x = 7  if x % 2 == 0:    print("Even") else:     print("Odd")

Output

Even Odd

Use lambda with map [Memory Efficient]

We have defined same as above logic with lambda and applied this to every list element using map

Python

a = [1, 2, 3, 4, 5]  res = map(lambda num: str(num) + " Even"            if num % 2 == 0 else str(num) + " Odd", a)  print("\n".join(res))

Output

1 Odd 2 Even 3 Odd 4 Even 5 Odd

Note: Using map is more memory-efficient because it creates an iterator instead of creating an entire list in memory.

Using Bitwise And(&) Operator

Another way to check whether a number is even or odd is by using the bitwise AND operator (&). In binary representation. Bitwise AND (&) operator gives 1 only for (1&1) otherwise it gives 0. So, knowing this we are going to evaluate the bitwise AND of a number with 1 and if the result is 1 number is odd, and if it is 0 number is even.

Python

x = 24  # If the least significant bit is 0 # the number is even otherwise, it's odd if x & 1 == 0:     print("Even") else:     print("Odd")          # Checking another number x = 7  if x & 1 == 0:     print("Even") else:     print("Odd")

Output

Even Odd

Python Program to Check Number is a Power of Two

rohit2sahu

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