Python Program for Legendre's Conjecture

Last Updated : 27 Jul, 2023

It says that there is always one prime number between any two consecutive natural number\'s(n = 1, 2, 3, 4, 5, ...) square. This is called Legendre's Conjecture. Conjecture: A conjecture is a proposition or conclusion based upon incomplete information to which no proof has been found i.e it has not been proved or disproved.

Mathematically, there is always one prime p in the range n^2 to (n + 1)^2 where n is any natural number. for examples- 2 and 3 are the primes in the range 1^2 to 2^2 . 5 and 7 are the primes in the range 2^2 to 3^2 . 11 and 13 are the primes in the range 3^2 to 4^2 . 17 and 19 are the primes in the range 4^2 to 5^2 .

Examples:

Input : 4 
output: Primes in the range 16 and 25 are:
        17
        19
        23

Explanation: Here 4² = 16 and 5² = 25 Hence, prime numbers between 16 and 25 are 17, 19 and 23.

Input : 10
Output: Primes in the range 100 and 121 are:
        101
        103
        107
        109
        113

Python3

# Python program to verify Legendre's Conjecture  # for a given n   import math   def isprime( n ):           i = 2     for i in range (2, int((math.sqrt(n)+1))):          if n%i == 0:              return False     return True      def LegendreConjecture( n ):      print ( "Primes in the range ", n*n              , " and ", (n+1)*(n+1)              , " are:" )                        for i in range (n*n, (((n+1)*(n+1))+1)):          if(isprime(i)):              print (i)               n = 50 LegendreConjecture(n)   # Contributed by _omg

Output :

Primes in the range 2500 and 2601 are:
2503
2521
2531
2539
2543
2549
2551
2557
2579
2591
2593

Time Complexity: O(n*sqrtn). isPrime() function takes O(n) time and it is embedded in LegendreConjecture() function which also takes O(n) time as it has loop which starts from n² and ends at
(n+1)² so, (n+1)² - n²= 2n+1.

Auxiliary Space: O(1)

METHOD 2:

Instead of iterating through a range of numbers to check for prime numbers, the new approach uses the sympy library to generate all prime numbers in a given range.

The sympy library provides the primesieve function, which takes two arguments: the start and end values for the range to search for primes.
The primesieve function returns a generator object that can be iterated over to get all the prime numbers in the specified range.
The isprime function is no longer necessary, as the primesieve function has already generated all prime numbers in the range.
The LegendreConjecture function remains the same, except for the for loop, which now iterates over the prime numbers.

NOTE: First you will have to install the sympy library using the following command: pip install sympy

Python3

import sympy  def LegendreConjecture(n):       # Find all prime numbers in the given range     primes = list(sympy.primerange(n*n, (n+1)*(n+1)))          # Print the prime numbers     print(f"Primes in the range {n*n} and {(n+1)*(n+1)} are:\n")     for i in range(len(primes)):       print(primes[i])      n = 50 LegendreConjecture(n)  # Contributed by adityasha4x71

Output :

Primes in the range 2500 and 2601 are:2503
2521
2531
2539
2543
2549
2551
2557
2579
2591
2593

Time complexity: O(n log log n), as the sieve of Eratosthenes algorithm has a time complexity of O(n log log n) for finding all primes up to n, and the algorithm used here is a modified version of the sieve of Eratosthenes.

Auxiliary Space: O(n), because the algorithm uses a boolean list of size n+1 to keep track of whether each number is prime or not.

Please refer complete article on Legendre's Conjecture for more details!

Python Program for Legendre's Conjecture

kartik

Improve

Article Tags :

Python Program for Legendre's Conjecture

METHOD 2:

Similar Reads