Python | Max/Min of tuple dictionary values

Last Updated : 22 Apr, 2023

Sometimes, while working with data, we can have a problem in which we need to find the min/max of tuple elements that are received as values of dictionary. We may have a problem to get index wise min/max. Let’s discuss certain ways in which this particular problem can be solved.

Method #1 : Using tuple() + min()/max() + zip() + values() The combination of above methods can be used to perform this particular task. In this, we just zip together equi index values extracted by values() using zip(). Then find min/max value using respective function. Finally result is returned as index wise max/min values as a tuple.

Python3

   # Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
# Using tuple() + min()/max() + zip() + values()
 
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
 
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
 
# Max / Min of tuple dictionary values
# Using tuple() + min()/max() + zip() + values()
res = tuple(max(x) for x in zip(*test_dict.values()))
 
# printing result
print("The maximum values from each index is : " + str(res))
 
  

Output :

The original dictionary is : {'is': (8, 3, 2), 'gfg': (5, 6, 1), 'best': (1, 4, 9)} The maximum values from each index is : (8, 6, 9)

Method #2 : Using tuple() + map() + values() + * operator This is yet another way in which this task can be performed. The difference is that we use map() instead of loop and * operator for zipping the values together.

Python3

   # Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
# Using tuple() + map() + values() + * operator
 
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
 
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
 
# Max / Min of tuple dictionary values
# Using tuple() + map() + values() + * operator
res = tuple(map(min, *test_dict.values()))
 
# printing result
print("The minimum values from each index is : " + str(res))
 
  

Output :

The original dictionary is : {'is': (8, 3, 2), 'gfg': (5, 6, 1), 'best': (1, 4, 9)} The minimum values from each index is : (1, 3, 1)

Method #3 : Using max(),keys(),tuple() methods

Approach

Initiate a for loop to traverse keys of dictionary
Append the max of each tuple value to output list
Convert the list to a tuple
Display tuple

Python3

   # Python3 code to demonstrate working of
# Max / Min of tuple dictionary values
 
# Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
 
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
 
# Max / Min of tuple dictionary values
x=list(test_dict.keys())
res=[]
for i in x:
    res.append(max(test_dict[i]))
res=tuple(res)
# printing result
print("The maximum values from each index is : " + str(res))
 
  

Output

The original dictionary is : {'gfg': (5, 6, 1), 'is': (8, 3, 2), 'best': (1, 4, 9)} The maximum values from each index is : (6, 8, 9)

Time Complexity : O(N)
Auxiliary Space : O(N)

Method #4: Using list comprehension and tuple()

You can use a list comprehension to iterate over the values of each key in the dictionary and find the maximum value for each index. Then you can convert the resulting list into a tuple.

Initialize a dictionary named test_dict with key-value pairs where the values are tuples of three integers. The keys are ‘gfg’, ‘is’, and ‘best’.
Print the original dictionary by using the print() function and converting the dictionary to a string using the str() function.
Create a list comprehension that iterates through each key in the test_dict dictionary.
For each key, call the max() function on the tuple value associated with that key to find the maximum value in the tuple.
Add each maximum value to a new list called res.
Convert the res list to a tuple using the tuple() function.
Print the result by using the print() function and converting the tuple to a string using the str() function. The result is the maximum value from each index of the tuples in the test_dict dictionary.

Python3

   # Initializing dictionary
test_dict = {'gfg' : (5, 6, 1), 'is' : (8, 3, 2), 'best' : (1, 4, 9)}
 
# printing original dictionary
print("The original dictionary is : " + str(test_dict))
 
# Max / Min of tuple dictionary values using Method #4
res = [max(test_dict[key]) for key in test_dict]
res = tuple(res)
 
# printing result
print("The maximum values from each index is : " + str(res))
 
  

Output

The original dictionary is : {'gfg': (5, 6, 1), 'is': (8, 3, 2), 'best': (1, 4, 9)} The maximum values from each index is : (6, 8, 9)

Time complexity: O(nm), where n is the number of keys in the dictionary and m is the length of the tuples.

Auxiliary space: O(n), where n is the number of keys in the dictionary.

Min and Max value in list of tuples-Python

manjeet_04

Improve

Article Tags :

Practice Tags :

python

Python | Max/Min of tuple dictionary values

Python3

Python3

Python3

Python3

Similar Reads