Python | math.isqrt() method

Last Updated : 25 Apr, 2025

Math module in Python contains a number of mathematical operations, which can be performed with ease using the module.
math.isqrt() method in Python is used to get the integer square root of the given non-negative integer value n. This method returns the floor value of the exact square root of n or equivalently the greatest integer a such that a² <= n.

Note: This method is new in Python version 3.8.

Syntax: math.isqrt(n)

Parameter:
n: A non-negative integer

Returns: an integer value which represents the floor of exact square root of the given non-negative integer n.

Code #1: Use of math.isqrt() method

Python3

# Python Program to explain # math.isqrt() method   import math  n = 10  # Get the floor value of # exact square root of n sqrt = math.isqrt(n) print(sqrt)  n = 100  # Get the floor value of  # exact square root of n sqrt = math.isqrt(n) print(sqrt)

Output:

3 10

Code #2: Use of math.isqrt() method to check whether the given integer is a perfect square.

Python3

# Python Program to explain  # math.isqrt() method   import math   def isPerfect(n):          # Get the floor value of     # exact square root of n     sqrt = math.isqrt(n)          if sqrt * sqrt == n:         print(f"{n} is perfect square")          else :         print(f"{n} is not a perfect square")    # Driver's code isPerfect(100) isPerfect(10)

Output:

100 is perfect square 10 is not a perfect square

Code #3: Use of math.isqrt() method to find the next perfect square of n.

Python3

# Python Program to explain # math.isqrt() method   import math  n = 11   def Next(n):          # Get the ceiling of     # exact square root of n      ceil = 1 + math.isqrt(n)          # print the next perfect square of n     print("Next perfect square of {} is {}".           format(n, ceil*ceil))   # Driver's code Next(11) Next(37)

Output:

Next perfect square after 11 is 16 Next perfect square after 37 is 49

Python | cmath.sqrt() method

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