Program to print reverse character bridge pattern

Last Updated : 20 Feb, 2023

For a given value N, denoting the number of Charters starting from the A, print reverse character bridge pattern.
Examples :

Input : n = 5  Output :     ABCDEDCBA   ABCD DCBA   ABC   CBA   AB     BA   A       A      Input : n = 8  Output :    ABCDEFGHGFEDCBA  ABCDEFG GFEDCBA  ABCDEF   FEDCBA  ABCDE     EDCBA  ABCD       DCBA  ABC         CBA  AB           BA  A             A

For a given value N, reflect the number of characters taking part in the pattern, starting from A. For N = 5, Participating character would be A B C D E.
By using a nested for loop we would compute the logic. Where the outer loop of 'i' would range from 0 to N and the inner loop of 'j' would range from 65(Start) to 64 + 2*N.
Under which we would check the required condition for the pattern design. For all the values of j which are less than ((64+n)+ i) it would print the (char)((64 + n)-( j % (64+n))) and for all the values of j <= ((64+n) -i) it would print (char)j.

C++

// CPP program to print reverse character bridge pattern #include <iostream> using namespace std;  // Function to print pattern void ReverseCharBridge(int n) {     for (int i = 0; i < n; i++)      {         for (int j = 'A'; j < 'A' + (2 * n) - 1; j++)          {             if (j >= ('A' + n - 1) + i)                 cout << (char)(('A' + n - 1) -                                 (j % ('A' + n - 1)));             else if (j <= ('A' + n - 1) - i)                 cout << (char)j;             else                 cout << " ";         }         cout << endl;     } }  // Driver Code int main() {     int n = 6;     ReverseCharBridge(n);     return 0; }

Java

// Java program to print reverse // character bridge pattern import java.io.*;  class GFG {          // Function to print pattern     static void ReverseCharBridge(int n)     {         for (int i = 0; i < n; i++)          {             for (int j = 'A'; j < 'A' + (2 * n) - 1; j++)              {               if (j >= ('A' + n - 1) + i)                 System.out.print((char)(('A' + n - 1) -                                   (j % ('A' + n - 1))));                 else if (j <= ('A' + n - 1) - i)                     System.out.print((char)j);                 else                     System.out.print(" ");             }             System.out.println();         }     }          // Driver Code     public static void main(String args[])     {         int n = 6;         ReverseCharBridge(n);     } }  /*This code is contributed by Nikita Tiwari.*/

Python3

# Python3 code to print reverse  # character bridge pattern  # Function to print pattern def ReverseCharBridge( n ):     for i in range( n ):         for j in range( ord('A'), ord('A') +                                (2 * n) - 1):             if j >= (ord( 'A' ) + n - 1) + i:                 print(chr((ord('A') + n - 1) -                    (j % (ord('A') + n - 1))), end = '')                          elif j <= (ord('A') + n - 1) - i:                 print(chr(j), end = '')             else:                 print(end = " ")         print("\n", end = '')          # Driver Code n = 6 ReverseCharBridge(n)  # This code is contributed by "Sharad_Bhardwaj".

// C# program to print reverse // character bridge pattern using System;  class GFG {      // Function to print pattern     static void ReverseCharBridge(int n)     {         for (int i = 0; i < n; i++)          {             for (int j = 'A'; j < 'A' + (2 * n) - 1; j++)             {                 if (j >= ('A' + n - 1) + i)                     Console.Write((char)(('A' + n - 1)                     - (j % ('A' + n - 1))));                                  else if (j <= ('A' + n - 1) - i)                     Console.Write((char)j);                                  else                     Console.Write(" ");             }             Console.WriteLine();         }     }      // Driver Code     public static void Main()     {         int n = 6;         ReverseCharBridge(n);     } }  // This code is contributed by vt_m.

PHP

<?php // PHP program to print reverse  // character bridge pattern  // Function to print pattern function ReverseCharBridge($n) {     //Ascii of A is 65     for ($i = 0; $i < $n; $i++)      {         for ($j = 65; $j < 65 +                 (2 * $n) - 1; $j++)          {             if ($j >= (65 + $n - 1) + $i)                 echo chr((65 + $n - 1) -                      ($j % (65 + $n - 1)));                                  else if ($j <= (65 + $n - 1) - $i)                 echo chr($j);             else                 echo " ";         }         echo "\n";     } }  // Driver Code $n = 6; ReverseCharBridge($n);  // This code is contributed by mits  ?>

JavaScript

<script> // Javascript program to print reverse character bridge pattern  // Function to print pattern function ReverseCharBridge(n) {     for (let i = 0; i < n; i++)      {         for (let j = 65; j < 65 + (2 * n) - 1; j++)          {             if (j >= (65 + n - 1) + i)                 document.write(String.fromCharCode((65 + n - 1) -                                 (j % (65 + n - 1))));             else if (j <= (65 + n - 1) - i)                 document.write(String.fromCharCode(j));             else                 document.write(" ");         }         document.write("\n");     } }  // Driver Code let n = 6; ReverseCharBridge(n);  // This code is contributed by Samim Hossain Mondal. </script>

Output

ABCDEFEDCBA  ABCDE EDCBA  ABCD   DCBA  ABC     CBA  AB       BA  A         A

Time Complexity: O(n²)

Auxiliary Space: O(1)

Program to print reverse character bridge pattern

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Program to print reverse character bridge pattern

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