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Program to print the Diamond Shape

Last Updated : 10 Jan, 2025
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Given a number n, write a program to print a diamond shape with 2n rows.

Examples : 

diamond

C++ 
// C++ program to print diamond shape // with 2n rows  #include <bits/stdc++.h> using namespace std;  // Prints diamond pattern with 2n rows  void printDiamond(int n)  {      int space = n - 1;       // run loop (parent loop)      // till number of rows      for (int i = 0; i < n; i++)      {          // loop for initially space,          // before star printing          for (int j = 0;j < space; j++)              cout << " ";           // Print i+1 stars          for (int j = 0; j <= i; j++)              cout << "* ";           cout << endl;          space--;      }       // Repeat again in reverse order      space = 0;       // run loop (parent loop)      // till number of rows      for (int i = n; i > 0; i--)      {          // loop for initially space,          // before star printing          for (int j = 0; j < space; j++)              cout << " ";           // Print i stars          for (int j = 0;j < i;j++)              cout << "* ";          cout << endl;         space++;      }  }   // Driver code  int main()  {      printDiamond(5);      return 0;  }   // This is code is contributed // by rathbhupendra
C 
// C program to print  // diamond shape with  // 2n rows #include<stdio.h>  // Prints diamond  // pattern with 2n rows void printDiamond(int n) {     int space = n - 1;      // run loop (parent loop)     // till number of rows     for (int i = 0; i < n; i++)     {         // loop for initially space,          // before star printing         for (int j = 0;j < space; j++)             printf(" ");          // Print i+1 stars         for (int j = 0;j <= i; j++)             printf("* ");          printf("\n");         space--;     }      // Repeat again in      // reverse order     space = 0;      // run loop (parent loop)     // till number of rows     for (int i = n; i > 0; i--)     {         // loop for initially space,          // before star printing         for (int j = 0; j < space; j++)             printf(" ");          // Print i stars         for (int j = 0;j < i;j++)             printf("* ");          printf("\n");         space++;     } }  // Driver code int main() {     printDiamond(5);     return 0; }
Java 
// JAVA Code to print  // the diamond shape import java.util.*;  class GFG {          // Prints diamond pattern     // with 2n rows     static void printDiamond(int n)     {         int space = n - 1;              // run loop (parent loop)          // till number of rows         for (int i = 0; i < n; i++)         {             // loop for initially space,              // before star printing             for (int j = 0; j < space; j++)                 System.out.print(" ");                  // Print i+1 stars             for (int j = 0; j <= i; j++)                 System.out.print("* ");                  System.out.print("\n");             space--;         }              // Repeat again in         // reverse order         space = 0;              // run loop (parent loop)          // till number of rows         for (int i = n; i > 0; i--)         {             // loop for initially space,              // before star printing             for (int j = 0; j < space; j++)                 System.out.print(" ");                  // Print i stars             for (int j = 0; j < i; j++)                 System.out.print("* ");                  System.out.print("\n");             space++;         }     }          // Driver Code     public static void main(String[] args)      {         printDiamond(5);              } }  // This code is contributed // by Arnav Kr. Mandal.
Python 
# Python program to # print Diamond shape  # Function to print # Diamond shape def Diamond(rows):     n = 1     for i in range(1, rows + 1):         # loop to print spaces         for j in range (1, (rows - i) + 1):             print(end = " ")                  # loop to print star         while n != (i+1):             print("*", end = " ")             n = n + 1         n = 1                  # line break         print()      k = 0     n = 0     for i in range(1, rows + 1):         # loop to print spaces         for j in range (1, k + 1):             print(end = " ")         k = k + 1                  # loop to print star         while n <= (rows - i):             print("*", end = " ")             n = n + 1         n = 0         print()  # Driver Code # number of rows input rows = 5 Diamond(rows)
C# 
// C# Code to print  // the diamond shape using System;  class GFG  {          // Prints diamond pattern     // with 2n rows     static void printDiamond(int n)     {         int space = n - 1;              // run loop (parent loop)          // till number of rows         for (int i = 0; i < n; i++)         {             // loop for initially space,             // before star printing             for (int j = 0; j < space; j++)                 Console.Write(" ");                  // Print i+1 stars             for (int j = 0; j <= i; j++)                 Console.Write("* ");                  Console.Write("\n");             space--;         }              // Repeat again in         // reverse order         space = 0;              // run loop (parent loop)         // till number of rows         for (int i = n; i > 0; i--)         {             // loop for initially space,              // before star printing             for (int j = 0; j < space; j++)                 Console.Write(" ");                  // Print i stars             for (int j = 0; j < i; j++)                 Console.Write("* ");                  Console.Write("\n");             space++;         }     }          // Driver Code     public static void Main()      {         printDiamond(5);              } }  // This code is contributed  // by Smitha Semwal.
JavaScript 
<script>       // JavaScript program to print diamond shape       // with 2n rows        // Prints diamond pattern with 2n rows       function printDiamond(n) {         var space = n - 1;          // run loop (parent loop)         // till number of rows         for (var i = 0; i < n; i++) {           // loop for initially space,           // before star printing           for (var j = 0; j < space; j++) document.write("&nbsp;&nbsp;");            // Print i+1 stars           for (var j = 0; j <= i; j++) document.write("*" + "&nbsp;&nbsp;");            document.write("<br>");           space--;         }          // Repeat again in reverse order         space = 0;          // run loop (parent loop)         // till number of rows         for (var i = n; i > 0; i--)          {                    // loop for initially space,           // before star printing           for (var j = 0; j < space; j++) document.write("&nbsp;&nbsp;");            // Print i stars           for (var j = 0; j < i; j++) document.write("*" + "&nbsp;&nbsp;");            document.write("<br>");           space++;         }       }        // Driver code       printDiamond(5);              // This code is contributed by rdtank.     </script>
PHP 
<?php // PHP program to print  // diamond shape with  // 2n rows  // Prints diamond $ // pattern with 2n rows function printDiamond($n) {     $space = $n - 1;      // run loop (parent loop)     // till number of rows     for ($i = 0; $i < $n; $i++)     {                  // loop for initially space,          // before star printing         for ($j = 0;$j < $space; $j++)             printf(" ");          // Print i+1 stars         for ($j = 0;$j <= $i; $j++)             printf("* ");          printf("\n");         $space--;     }      // Repeat again in      // reverse order     $space = 0;      // run loop (parent loop)     // till number of rows     for ($i = $n; $i > 0; $i--)     {                  // loop for initially space,          // before star printing         for ($j = 0; $j < $space; $j++)             printf(" ");          // Pr$i stars         for ($j = 0;$j < $i;$j++)             printf("* ");          printf("\n");         $space++;     } }      // Driver code     printDiamond(5);  // This code is contributed by Anuj_67 ?>

Output
    *     * *    * * *   * * * *  * * * * *  * * * * *   * * * *    * * *     * *      *

Time Complexity: O(n*n) since we are traversing rows and columns of a grid for printing spaces ' ' and star '*'.
Auxiliary Space: O(1), No extra Space used.

Approach 2: Solving the problem using Recursion

Below is the implementation of the above approach:

C++ 
// C++ program to print diamond pattern using recursion #include <bits/stdc++.h> using namespace std; void gotonextLine(int k, int i, int z) {     if (k == i) // base case         return;     cout << "* ";     gotonextLine(k + z, i, z); } void addblankSpaceInDiamond(     int j, int i, int z) // print blank space of diamond {     if (j == i)         return;     cout << " ";     addblankSpaceInDiamond(j + z, i, z); } void upperDiamond(int row, int i) {     if (i > row) // base case         return;     addblankSpaceInDiamond(row, i, -1);     gotonextLine(0, i, 1);     cout << endl;     upperDiamond(row, i + 1); // recursive call } void lowerDiamond(int row,                   int i) // print the next line of diamond {     if (i > row) // base case         return;     addblankSpaceInDiamond(0, i, 1);     gotonextLine(row, i, -1);     cout << endl;     lowerDiamond(row, i + 1); } int main() {     int row;     row = 5;     upperDiamond(row, 0); // print upper part of triangle     lowerDiamond(row, 1); // print lower part of diamond     return 0;     // this code is contributed by Shivesh Kumar Dwivedi }
Java 
// Java program to print diamond pattern using recursion import java.io.*;   class GFG{       static void gotonextLine(int k, int i, int z) {     if (k == i) // base case         return;     System.out.print("* ");     gotonextLine(k + z, i, z); } static void addblankSpaceInDiamond(int j, int i, int z) // print blank space of diamond {     if (j == i)         return;     System.out.print(" ");     addblankSpaceInDiamond(j + z, i, z); }  static void upperDiamond(int row, int i) {     if (i > row) // base case         return;     addblankSpaceInDiamond(row, i, -1);     gotonextLine(0, i, 1);     System.out.print("\n");     upperDiamond(row, i + 1); // recursive call } static void lowerDiamond(int row, int i) // print the next line of diamond {     if (i > row) // base case         return;     addblankSpaceInDiamond(0, i, 1);     gotonextLine(row, i, -1);     System.out.print("\n");     lowerDiamond(row, i + 1); }   // Driver Code public static void main(String[] args) {     int row;     row = 5;     upperDiamond(row, 0); // print upper part of triangle     lowerDiamond(row, 1); // print lower part of diamond } }   // This code is contributed by adityapatil12
Python 
def gotonextLine(k, i, z):   # base case     if (k == i):       return     print("* ", end=""),     gotonextLine(k + z, i, z)  # print blank space of diamond def addblankSpaceInDiamond(j,i,z):     if (j == i):       return     print(" ",end=""),     addblankSpaceInDiamond(j + z, i, z)  def upperDiamond(row,i):   # base case     if (i > row):       return     addblankSpaceInDiamond(row, i, -1)     gotonextLine(0, i, 1)     print("\n",end=""),     upperDiamond(row, i + 1) # recursive call   def lowerDiamond(row,i):   # print the next line of diamond     if (i > row): # base case       return     addblankSpaceInDiamond(0, i, 1)     gotonextLine(row, i, -1)     print("\n",end=""),     lowerDiamond(row, i + 1)  # Code row = 5 upperDiamond(row, 0) # print upper part of triangle lowerDiamond(row, 1) # print lower part of diamond  # This code is contributed by akashish__
C# 
using System;  public class GFG{    public static void gotonextLine(int k, int i, int z)   {     if (k == i) // base case       return;     Console.Write("* ");     gotonextLine(k + z, i, z);   }    public static void addblankSpaceInDiamond(     int j, int i, int z) // print blank space of diamond   {     if (j == i)       return;     Console.Write(" ");     addblankSpaceInDiamond(j + z, i, z);   }    public static void upperDiamond(int row, int i)   {     if (i > row) // base case       return;     addblankSpaceInDiamond(row, i, -1);     gotonextLine(0, i, 1);     Console.Write("\n");     upperDiamond(row, i + 1); // recursive call   }     public static void lowerDiamond(int row,                                   int i) // print the next line of diamond   {     if (i > row) // base case       return;     addblankSpaceInDiamond(0, i, 1);     gotonextLine(row, i, -1);     Console.Write("\n");     lowerDiamond(row, i + 1);   }    public static void Main ()   {      // Code     int row;     row = 5;     upperDiamond(row, 0); // print upper part of triangle     lowerDiamond(row, 1); // print lower part of diamond   } }  // This code is contributed by akashish__
JavaScript 
    // JavaScript program to print diamond pattern using recursion              function gotonextLine(k, i, z)     {         if (k == i) // base case             return;         console.log("*&nbsp;");         gotonextLine(k + z, i, z);     }     function addblankSpaceInDiamond(j, i, z) // print blank space of diamond     {         if (j == i)             return;         console.log("&nbsp;");         addblankSpaceInDiamond(j + z, i, z);     }      function upperDiamond(row, i)     {         if (i > row) // base case             return;         addblankSpaceInDiamond(row, i, -1);         gotonextLine(0, i, 1);         console.log("<br>");         upperDiamond(row, i + 1); // recursive call     }     function lowerDiamond(row, i) // print the next line of diamond     {         if (i > row) // base case             return;         addblankSpaceInDiamond(0, i, 1);         gotonextLine(row, i, -1);         console.log("<br>");         lowerDiamond(row, i + 1);     }           // Driver Code          let row;         row = 5;         upperDiamond(row, 0); // print upper part of triangle         lowerDiamond(row, 1); // print lower part of diamond          // This code is contributed by agfro1cac

Output
          *     * *    * * *   * * * *  * * * * *   * * * *    * * *     * *      *

Time Complexity: O(N2), Since we are traversing rows and columns of a grid for printing spaces ' ' and star '*'.
Auxiliary Space: O(N), The extra space is used in recursion call stack.


R

Rahul Singh(Nit KKR)
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Article Tags :
  • Python
  • C Language
  • C++
  • DSA
  • Basic Coding Problems
  • pattern-printing
  • Python Pattern-printing
Practice Tags :
  • CPP
  • pattern-printing
  • python

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    List comprehension and Lambda Function in Python
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    Python Pattern printing Exercises

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    Python program to print the Inverted heart pattern
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    Program to Print K using Alphabets
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    Program to print half Diamond star pattern
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    Python Program to print a number diamond of any given size N in Rangoli Style
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    Python | Print an Inverted Star Pattern
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    Program to print the Diamond Shape
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