numpy.isfortran() in Python

Last Updated : 29 Nov, 2018

numpy.isfortran(array) : This is a logical function that checks whether array is Fortran contiguous or not.

Order : [C-contiguous, F-contiguous, A-contiguous; optional]

C-contiguous order in memory(last index varies the fastest). C order means that operating row-rise on the array will be slightly quicker.
FORTRAN-contiguous order in memory (first index varies the fastest). F order means that column-wise operations will be faster.
‘A’ means to read / write the elements in Fortran-like index order if, array is Fortran contiguous in memory, C-like order otherwise.

Parameters :

  array    : [array_like]Input array

Return :

  True, if array is Fortran; else False

Code 1 :

   # Python program explaining 
# isfortran() function 
import numpy as np 
  
in_array = np.array([[1, 2, 3], [4, 5, 6]], order='C') 
print ("Input array : \n", in_array) 
  
exp2_values = np.exp2(in_array) 
print ("\nisfortran : ", np.isfortran(in_array)) 
 
  

Output :

  Input array :    [[1 2 3]   [4 5 6]]    isfortran :  False

Code 2 :

   # Python program explaining 
# isfortran() function 
import numpy as np 
  
in_array = np.array([[1, 2, 3], [4, 5, 6]], order='F') 
print ("Input array : \n", in_array) 
  
exp2_values = np.exp2(in_array) 
print ("\nisfortran : ", np.isfortran(in_array)) 
 
  

Output :

Input array :    [[1 2 3]   [4 5 6]]    isfortran :  True

References :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.isfortran.html#numpy.isfortran
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