Skip to content
geeksforgeeks
  • Courses
    • DSA to Development
    • Get IBM Certification
    • Newly Launched!
      • Master Django Framework
      • Become AWS Certified
    • For Working Professionals
      • Interview 101: DSA & System Design
      • Data Science Training Program
      • JAVA Backend Development (Live)
      • DevOps Engineering (LIVE)
      • Data Structures & Algorithms in Python
    • For Students
      • Placement Preparation Course
      • Data Science (Live)
      • Data Structure & Algorithm-Self Paced (C++/JAVA)
      • Master Competitive Programming (Live)
      • Full Stack Development with React & Node JS (Live)
    • Full Stack Development
    • Data Science Program
    • All Courses
  • Tutorials
    • Data Structures & Algorithms
    • ML & Data Science
    • Interview Corner
    • Programming Languages
    • Web Development
    • CS Subjects
    • DevOps And Linux
    • School Learning
  • Practice
    • Build your AI Agent
    • GfG 160
    • Problem of the Day
    • Practice Coding Problems
    • GfG SDE Sheet
  • Contests
    • Accenture Hackathon (Ending Soon!)
    • GfG Weekly [Rated Contest]
    • Job-A-Thon Hiring Challenge
    • All Contests and Events
  • DSA
  • Interview Problems on Linked List
  • Practice Linked List
  • MCQs on Linked List
  • Linked List Tutorial
  • Types of Linked List
  • Singly Linked List
  • Doubly Linked List
  • Circular Linked List
  • Circular Doubly Linked List
  • Linked List vs Array
  • Time & Space Complexity
  • Advantages & Disadvantages
Open In App
Next Article:
Find a permutation that causes worst case of Merge Sort
Next article icon

Merge a linked list into another linked list at alternate positions

Last Updated : 13 Sep, 2024
Comments
Improve
Suggest changes
Like Article
Like
Report

Given two singly linked lists, The task is to insert nodes of the second list into the first list at alternate positions of the first list and leave the remaining nodes of the second list if it is longer.

Example:

Input: head1: 1->2->3 , head2: 4->5->6->7->8
Output: head1: 1->4->2->5->3->6 , head2: 7->8

4_1


Input: head1: 10->12->21 , head2: 3->1->4
Output: head1: 10->3->12->1->21->4, head2: <empty>

2_3

Using Iterative Method – O(n) Time and O(1) Space:

The idea is to start traversing from the beginning of both lists. For each step, take a node from the second list and insert it after a node from the first list. This process continues until we reach the end of one or both lists. If the second list is longer, remaining nodes will be kept as it is second list.

C++ 
// C++ program to merge a linked list into another at // alternate positions  #include <bits/stdc++.h> using namespace std;  class Node{   public:     int data;     Node *next;     Node(int x) {         data = x;         next = nullptr;     } };  void printList(Node *head){     Node *curr = head;     while (curr != NULL){         cout << curr->data << " ";         curr = curr->next;     }     cout << endl; }  // Function to merge two linked lists vector<Node *> merge(Node *head1, Node *head2) {        // Initialize pointers to traverse the two lists     Node *curr1 = head1;     Node *curr2 = head2;      // Traverse both lists and merge them     while (curr1 != NULL && curr2 != NULL){                // Save the next nodes of the current        	// nodes in both lists         Node *ptr1 = curr1->next;         Node *ptr2 = curr2->next;          // Insert the current node from the second list         // after the current node from the first list         curr2->next = curr1->next;         curr1->next = curr2;          // Update the pointers for the next iteration         curr1 = ptr1;         curr2 = ptr2;     }      return {head1, curr2}; }  int main(){        // Creating first linked list 1->2->3     Node *head1 = new Node(1);     head1->next = new Node(2);     head1->next->next = new Node(3);      // crating second listed list 4->5->6->7->8     Node *head2 = new Node(4);     head2->next = new Node(5);     head2->next->next = new Node(6);     head2->next->next->next = new Node(7);     head2->next->next->next->next = new Node(8);      // Store first and second head points in array     vector<Node *> ar = merge(head1, head2);     printList(ar[0]);     printList(ar[1]);      return 0; }
C 
// C program to merge a linked list into another at // alternate positions #include <stdio.h> #include <stdlib.h>  struct Node {     int data;     struct Node *next; };   void printList(struct Node *head) {     struct Node *curr = head;     while (curr != NULL) {         printf("%d ", curr->data);         curr = curr->next;     }     printf("\n"); }  // Function to merge two linked lists struct Node *merge(struct Node *head1, struct Node *head2) {     struct Node *curr1 = head1;     struct Node *curr2 = head2;     struct Node *next1, *next2;      // Traverse both lists and merge them     while (curr1 != NULL && curr2 != NULL) {                // Save the next nodes of the current        	//  nodes in both lists         next1 = curr1->next;         next2 = curr2->next;          // Insert the current node from the second list       	// after the current node from the first list         curr2->next = curr1->next;         curr1->next = curr2;          // Update the pointers for the next iteration         curr1 = next1;         curr2 = next2;     }      // Return the remaining part of the second list     return curr2; }  struct Node *createNode(int data) {     struct Node *newNode =        (struct Node *)malloc(sizeof(struct Node));     newNode->data = data;     newNode->next = NULL;     return newNode; }  int main() {        // Creating the first linked list: 1->2->3     struct Node *head1 = createNode(1);     head1->next = createNode(2);     head1->next->next = createNode(3);      // Creating the second linked list: 4->5->6->7->8     struct Node *head2 = createNode(4);     head2->next = createNode(5);     head2->next->next = createNode(6);     head2->next->next->next = createNode(7);     head2->next->next->next->next = createNode(8);      struct Node *remaining = merge(head1, head2);      // Print merged list and remaining list     printList(head1);     printList(remaining);      return 0; }
Java 
// Java program to merge a linked list into another at // alternate positions  import java.util.*;  class Node {     int data;     Node next;      Node(int x) {         data = x;         next = null;     } }  class GfG {      // Function to print a linked list     static void printList(Node head) {         Node curr = head;         while (curr != null) {             System.out.print(curr.data + " ");             curr = curr.next;         }         System.out.println();     }      // Function to merge two linked lists     static List<Node> merge(Node head1, Node head2) {                // Initialize pointers to traverse the two lists         Node temp1 = head1;         Node temp2 = head2;          // Traverse both lists and merge them         while (temp1 != null && temp2 != null) {                        // Save the next nodes of the current nodes in             // both lists             Node ptr1 = temp1.next;             Node ptr2 = temp2.next;              // Insert the current node from the second list             // after the current node from the first list             temp2.next = temp1.next;             temp1.next = temp2;              // Update the pointers for the next iteration             temp1 = ptr1;             temp2 = ptr2;         }          return Arrays.asList(head1, temp2);     }      public static void main(String[] args) {          // Creating first linked list 1->2->3         Node head1 = new Node(1);         head1.next = new Node(2);         head1.next.next = new Node(3);          // Creating second linked list 4->5->6->7->8         Node head2 = new Node(4);         head2.next = new Node(5);         head2.next.next = new Node(6);         head2.next.next.next = new Node(7);         head2.next.next.next.next = new Node(8);          // Store first and second head points in array         List<Node> ar = merge(head1, head2);         printList(ar.get(0));         printList(ar.get(1));     } }
Python 
# Python program to merge a linked list into another at # alternate positions class Node:     def __init__(self, x):         self.data = x         self.next = None   def printList(head):     curr = head     while curr:         print(curr.data, end=" ")         curr = curr.next     print()  # Function to merge two linked lists def merge(head1, head2):        # Initialize pointers to traverse the two lists     temp1 = head1     temp2 = head2      # Traverse both lists and merge them     while temp1 is not None and temp2 is not None:                # Save the next nodes of the current         # nodes in both lists         ptr1 = temp1.next         ptr2 = temp2.next          # Insert the current node from the second list         # after the current node from the first list         temp2.next = temp1.next         temp1.next = temp2          # Update the pointers for the next iteration         temp1 = ptr1         temp2 = ptr2      return [head1, temp2]   if __name__ == "__main__":        # Creating first linked list 1->2->3     head1 = Node(1)     head1.next = Node(2)     head1.next.next = Node(3)      # Creating second linked list 4->5->6->7->8     head2 = Node(4)     head2.next = Node(5)     head2.next.next = Node(6)     head2.next.next.next = Node(7)     head2.next.next.next.next = Node(8)      # Store first and second head points in array     ar = merge(head1, head2)     printList(ar[0])     printList(ar[1])
C# 
// C# program to merge a linked list into // another at alternate positions  using System; using System.Collections.Generic;  class Node {     public int data;     public Node next;      public Node(int x) {         data = x;         next = null;     } }  class GfG {      static void PrintList(Node head) {         Node curr = head;         while (curr != null) {             Console.Write(curr.data + " ");             curr = curr.next;         }         Console.WriteLine();     }      // Function to merge two linked lists     static List<Node> Merge(Node head1, Node head2) {                // Initialize pointers to traverse the two lists         Node temp1 = head1;         Node temp2 = head2;          // Traverse both lists and merge them         while (temp1 != null && temp2 != null) {                        // Save the next nodes of the current nodes in             // both lists             Node ptr1 = temp1.next;             Node ptr2 = temp2.next;              // Insert the current node from the second list             // after the current node from the first list             temp2.next = temp1.next;             temp1.next = temp2;              // Update the pointers for the next iteration             temp1 = ptr1;             temp2 = ptr2;         }          return new List<Node>{ head1, temp2 };     }      static void Main(string[] args) {                // Creating first linked list 1->2->3         Node head1 = new Node(1);         head1.next = new Node(2);         head1.next.next = new Node(3);          // Creating second linked list 4->5->6->7->8         Node head2 = new Node(4);         head2.next = new Node(5);         head2.next.next = new Node(6);         head2.next.next.next = new Node(7);         head2.next.next.next.next = new Node(8);          // Store first and second head points in array         List<Node> ar = Merge(head1, head2);         PrintList(ar[0]);         PrintList(ar[1]);     } }
JavaScript 
// Javascript program to merge a linked list // into another at alternate positions  class Node {     constructor(x) {         this.data = x;         this.next = null;     } }  function printList(head) {     let curr = head;     while (curr !== null) {         console.log(curr.data + " ");         curr = curr.next;     }     console.log(); }  // Function to merge two linked lists function merge(head1, head2) {      // Initialize pointers to traverse the two lists     let temp1 = head1;     let temp2 = head2;      // Traverse both lists and merge them     while (temp1 !== null && temp2 !== null) {              // Save the next nodes of the current nodes in both         // lists         let ptr1 = temp1.next;         let ptr2 = temp2.next;          // Insert the current node from the second list         // after the current node from the first list         temp2.next = temp1.next;         temp1.next = temp2;          // Update the pointers for the next iteration         temp1 = ptr1;         temp2 = ptr2;     }      return [ head1, temp2 ]; }  // Creating first linked list 1->2->3 let head1 = new Node(1); head1.next = new Node(2); head1.next.next = new Node(3);  // Creating second linked list 4->5->6->7->8 let head2 = new Node(4); head2.next = new Node(5); head2.next.next = new Node(6); head2.next.next.next = new Node(7); head2.next.next.next.next = new Node(8);  // Store first and second head points in array let ar = merge(head1, head2); printList(ar[0]); printList(ar[1]);

Output
1 4 2 5 3 6  7 8

Time Complexity: O(min(n1, n2)), where n1 and n2 represents the length of the given two linked lists.
Auxiliary Space: O(1).



Next Article
Find a permutation that causes worst case of Merge Sort
author
kartik
Improve
Article Tags :
  • DSA
  • Linked List
  • Amazon
Practice Tags :
  • Amazon
  • Linked List

Similar Reads

  • Merge Sort - Data Structure and Algorithms Tutorials
    Merge sort is a popular sorting algorithm known for its efficiency and stability. It follows the divide-and-conquer approach. It works by recursively dividing the input array into two halves, recursively sorting the two halves and finally merging them back together to obtain the sorted array. How do
    14 min read

    • Merge sort in different languages

    • C Program for Merge Sort
      Merge Sort is a comparison-based sorting algorithm that works by dividing the input array into two halves, then calling itself for these two halves, and finally it merges the two sorted halves. In this article, we will learn how to implement merge sort in C language. What is Merge Sort Algorithm?Mer
      3 min read
    • C++ Program For Merge Sort
      Merge Sort is a comparison-based sorting algorithm that uses divide and conquer paradigm to sort the given dataset. It divides the dataset into two halves, calls itself for these two halves, and then it merges the two sorted halves. In this article, we will learn how to implement merge sort in a C++
      4 min read
    • Java Program for Merge Sort
      Merge Sort is a divide-and-conquer algorithm. It divides the input array into two halves, calls itself the two halves, and then merges the two sorted halves. The merge() function is used for merging two halves. The merge(arr, l, m, r) is a key process that assumes that arr[l..m] and arr[m+1..r] are
      3 min read
    • Merge Sort in Python
      Merge Sort is a Divide and Conquer algorithm. It divides input array in two halves, calls itself for the two halves and then merges the two sorted halves. The merge() function is used for merging two halves. The merge(arr, l, m, r) is key process that assumes that arr[l..m] and arr[m+1..r] are sorte
      4 min read
    • Merge Sort using Multi-threading
      Merge Sort is a popular sorting technique which divides an array or list into two halves and then start merging them when sufficient depth is reached. Time complexity of merge sort is O(nlogn).Threads are lightweight processes and threads shares with other threads their code section, data section an
      14 min read

    Variations of Merge Sort

    • 3-way Merge Sort
      Merge Sort is a divide-and-conquer algorithm that recursively splits an array into two halves, sorts each half, and then merges them. A variation of this is 3-way Merge Sort, where instead of splitting the array into two parts, we divide it into three equal parts. In traditional Merge Sort, the arra
      14 min read
    • Iterative Merge Sort
      Given an array of size n, the task is to sort the given array using iterative merge sort. Examples: Input: arr[] = [4, 1, 3, 9, 7]Output: [1, 3, 4, 7, 9]Explanation: The output array is sorted. Input: arr[] = [1, 3 , 2]Output: [1, 2, 3]Explanation: The output array is sorted. You can refer to Merge
      9 min read
    • In-Place Merge Sort
      Implement Merge Sort i.e. standard implementation keeping the sorting algorithm as in-place. In-place means it does not occupy extra memory for merge operation as in the standard case. Examples: Input: arr[] = {2, 3, 4, 1} Output: 1 2 3 4 Input: arr[] = {56, 2, 45} Output: 2 45 56 Approach 1: Mainta
      15+ min read
    • In-Place Merge Sort | Set 2
      Given an array A[] of size N, the task is to sort the array in increasing order using In-Place Merge Sort. Examples: Input: A = {5, 6, 3, 2, 1, 6, 7}Output: {1, 2, 3, 5, 6, 6, 7} Input: A = {2, 3, 4, 1}Output: {1, 2, 3, 4} Approach: The idea is to use the inplace_merge() function to merge the sorted
      7 min read
    • Merge Sort with O(1) extra space merge and O(n log n) time [Unsigned Integers Only]
      We have discussed Merge sort. How to modify the algorithm so that merge works in O(1) extra space and algorithm still works in O(n Log n) time. We may assume that the input values are integers only. Examples: Input : 5 4 3 2 1 Output : 1 2 3 4 5 Input : 999 612 589 856 56 945 243 Output : 56 243 589
      10 min read

    Merge Sort in Linked List

    • Merge Sort for Linked Lists
      Given a singly linked list, The task is to sort the linked list in non-decreasing order using merge sort. Examples: Input: 40 -> 20 -> 60 -> 10 -> 50 -> 30 -> NULLOutput: 10 -> 20 -> 30 -> 40 -> 50 -> 60 -> NULL Input: 9 -> 5 -> 2 -> 8 -> NULLOutput: 2
      12 min read
    • Merge Sort for Doubly Linked List
      Given a doubly linked list, The task is to sort the doubly linked list in non-decreasing order using merge sort.Examples: Input: 10 <-> 8 <-> 4 <-> 2Output: 2 <-> 4 <-> 8 <-> 10Input: 5 <-> 3 <-> 2Output: 2 <-> 3 <-> 5 Note: Merge sort for
      13 min read
    • Iterative Merge Sort for Linked List
      Given a singly linked list of integers, the task is to sort it using iterative merge sort. Examples: Input: 40 -> 20 -> 60 -> 10 -> 50 -> 30 -> NULLOutput: 10 -> 20 -> 30 -> 40 -> 50 -> 60 -> NULL Input: 9 -> 5 -> 2 -> 8 -> NULLOutput: 2 -> 5 ->
      14 min read
    • Merge two sorted lists (in-place)
      Given two sorted linked lists consisting of n and m nodes respectively. The task is to merge both of the lists and return the head of the merged list. Example: Input: Output: Input: Output: Approach: The idea is to iteratively merge two sorted linked lists using a dummy node to simplify the process.
      9 min read
    • Merge K sorted Doubly Linked List in Sorted Order
      Given K sorted doubly linked list. The task is to merge all sorted doubly linked list in single sorted doubly linked list means final list must be sorted.Examples: Input: List 1 : 2 <-> 7 <-> 8 <-> 12 <-> 15 <-> NULL List 2 : 4 <-> 9 <-> 10 <-> NULL Li
      15+ min read
    • Merge a linked list into another linked list at alternate positions
      Given two singly linked lists, The task is to insert nodes of the second list into the first list at alternate positions of the first list and leave the remaining nodes of the second list if it is longer. Example: Input: head1: 1->2->3 , head2: 4->5->6->7->8Output: head1: 1->4-
      8 min read
  • Find a permutation that causes worst case of Merge Sort
    Given a set of elements, find which permutation of these elements would result in worst case of Merge Sort.Asymptotically, merge sort always takes O(n Log n) time, but the cases that require more comparisons generally take more time in practice. We basically need to find a permutation of input eleme
    12 min read
  • How to make Mergesort to perform O(n) comparisons in best case?
    As we know, Mergesort is a divide and conquer algorithm that splits the array to halves recursively until it reaches an array of the size of 1, and after that it merges sorted subarrays until the original array is fully sorted. Typical implementation of merge sort works in O(n Log n) time in all thr
    3 min read
  • Concurrent Merge Sort in Shared Memory
    Given a number 'n' and a n numbers, sort the numbers using Concurrent Merge Sort. (Hint: Try to use shmget, shmat system calls).Part1: The algorithm (HOW?) Recursively make two child processes, one for the left half, one of the right half. If the number of elements in the array for a process is less
    10 min read

    • Visualization of Merge Sort

    • Sorting Algorithm Visualization : Merge Sort
      The human brain can easily process visuals instead of long codes to understand the algorithms. In this article, a program that program visualizes the Merge sort Algorithm has been implemented. The GUI(Graphical User Interface) is implemented using pygame package in python. Approach: An array of rand
      3 min read
    • Merge Sort Visualization in JavaScript
      GUI(Graphical User Interface) helps users with better understanding programs. In this article, we will visualize Merge Sort using JavaScript. We will see how the arrays are divided and merged after sorting to get the final sorted array.  Refer: Merge SortCanvas in HTMLAsynchronous Function in JavaSc
      4 min read
    • Visualize Merge sort Using Tkinter in Python
      Prerequisites: Python GUI – tkinter In this article, we will create a GUI application that will help us to visualize the algorithm of merge sort using Tkinter in Python. Merge Sort is a popular sorting algorithm. It has a time complexity of N(logN) which is faster than other sorting algorithms like
      5 min read
    • Visualization of Merge sort using Matplotlib
      Prerequisites: Introduction to Matplotlib, Merge Sort Visualizing algorithms makes it easier to understand them by analyzing and comparing the number of operations that took place to compare and swap the elements. For this we will use matplotlib, to plot bar graphs to represent the elements of the a
      3 min read
    • 3D Visualisation of Merge Sort using Matplotlib
      Visualizing algorithms makes it easier to understand them by analyzing and comparing the number of operations that took place to compare and swap the elements. 3D visualization of algorithms is less common, for this we will use matplotlib to plot bar graphs and animate them to represent the elements
      3 min read

    Some problems on Merge Sort

    • Count Inversions of an Array
      Given an integer array arr[] of size n, find the inversion count in the array. Two array elements arr[i] and arr[j] form an inversion if arr[i] > arr[j] and i < j. Note: Inversion Count for an array indicates that how far (or close) the array is from being sorted. If the array is already sorte
      15+ min read
    • Count of smaller elements on right side of each element in an Array using Merge sort
      Given an array arr[] of N integers, the task is to count the number of smaller elements on the right side for each of the element in the array Examples: Input: arr[] = {6, 3, 7, 2} Output: 2, 1, 1, 0 Explanation: Smaller elements after 6 = 2 [3, 2] Smaller elements after 3 = 1 [2] Smaller elements a
      12 min read
    • Sort a nearly sorted (or K sorted) array
      Given an array arr[] and a number k . The array is sorted in a way that every element is at max k distance away from it sorted position. It means if we completely sort the array, then the index of the element can go from i - k to i + k where i is index in the given array. Our task is to completely s
      6 min read
    • Median of two Sorted Arrays of Different Sizes
      Given two sorted arrays, a[] and b[], the task is to find the median of these sorted arrays. Assume that the two sorted arrays are merged and then median is selected from the combined array. This is an extension of Median of two sorted arrays of equal size problem. Here we handle arrays of unequal s
      15+ min read
    • Merge k Sorted Arrays
      Given K sorted arrays, merge them and print the sorted output. Examples: Input: K = 3, arr = { {1, 3, 5, 7}, {2, 4, 6, 8}, {0, 9, 10, 11}}Output: 0 1 2 3 4 5 6 7 8 9 10 11 Input: k = 4, arr = { {1}, {2, 4}, {3, 7, 9, 11}, {13} }Output: 1 2 3 4 7 9 11 13 Table of Content Naive - Concatenate all and S
      15+ min read
    • Merge K sorted arrays of different sizes | ( Divide and Conquer Approach )
      Given k sorted arrays of different length, merge them into a single array such that the merged array is also sorted.Examples: Input : {{3, 13}, {8, 10, 11} {9, 15}} Output : {3, 8, 9, 10, 11, 13, 15} Input : {{1, 5}, {2, 3, 4}} Output : {1, 2, 3, 4, 5} Let S be the total number of elements in all th
      8 min read
    • Merge K sorted linked lists
      Given k sorted linked lists of different sizes, the task is to merge them all maintaining their sorted order. Examples: Input: Output: Merged lists in a sorted order where every element is greater than the previous element. Input: Output: Merged lists in a sorted order where every element is greater
      15+ min read
    • Union and Intersection of two Linked List using Merge Sort
      Given two singly Linked Lists, create union and intersection lists that contain the union and intersection of the elements present in the given lists. Each of the two lists contains distinct node values. Note: The order of elements in output lists doesn't matter. Examples: Input: head1: 10 -> 15
      15+ min read
    • Sorting by combining Insertion Sort and Merge Sort algorithms
      Insertion sort: The array is virtually split into a sorted and an unsorted part. Values from the unsorted part are picked and placed at the correct position in the sorted part.Advantages: Following are the advantages of insertion sort: If the size of the list to be sorted is small, insertion sort ru
      2 min read
    • Find array with k number of merge sort calls
      Given two numbers n and k, find an array containing values in [1, n] and requires exactly k calls of recursive merge sort function. Examples: Input : n = 3 k = 3 Output : a[] = {2, 1, 3} Explanation: Here, a[] = {2, 1, 3} First of all, mergesort(0, 3) will be called, which then sets mid = 1 and call
      6 min read
    • Difference of two Linked Lists using Merge sort
      Given two Linked List, the task is to create a Linked List to store the difference of Linked List 1 with Linked List 2, i.e. the elements present in List 1 but not in List 2.Examples: Input: List1: 10 -> 15 -> 4 ->20, List2: 8 -> 4 -> 2 -> 10 Output: 15 -> 20 Explanation: In the
      14 min read
geeksforgeeks-footer-logo
Corporate & Communications Address:
A-143, 7th Floor, Sovereign Corporate Tower, Sector- 136, Noida, Uttar Pradesh (201305)
Registered Address:
K 061, Tower K, Gulshan Vivante Apartment, Sector 137, Noida, Gautam Buddh Nagar, Uttar Pradesh, 201305
GFG App on Play Store GFG App on App Store
Advertise with us
  • Company
  • About Us
  • Legal
  • Privacy Policy
  • In Media
  • Contact Us
  • Advertise with us
  • GFG Corporate Solution
  • Placement Training Program
  • Languages
  • Python
  • Java
  • C++
  • PHP
  • GoLang
  • SQL
  • R Language
  • Android Tutorial
  • Tutorials Archive
  • DSA
  • Data Structures
  • Algorithms
  • DSA for Beginners
  • Basic DSA Problems
  • DSA Roadmap
  • Top 100 DSA Interview Problems
  • DSA Roadmap by Sandeep Jain
  • All Cheat Sheets
  • Data Science & ML
  • Data Science With Python
  • Data Science For Beginner
  • Machine Learning
  • ML Maths
  • Data Visualisation
  • Pandas
  • NumPy
  • NLP
  • Deep Learning
  • Web Technologies
  • HTML
  • CSS
  • JavaScript
  • TypeScript
  • ReactJS
  • NextJS
  • Bootstrap
  • Web Design
  • Python Tutorial
  • Python Programming Examples
  • Python Projects
  • Python Tkinter
  • Python Web Scraping
  • OpenCV Tutorial
  • Python Interview Question
  • Django
  • Computer Science
  • Operating Systems
  • Computer Network
  • Database Management System
  • Software Engineering
  • Digital Logic Design
  • Engineering Maths
  • Software Development
  • Software Testing
  • DevOps
  • Git
  • Linux
  • AWS
  • Docker
  • Kubernetes
  • Azure
  • GCP
  • DevOps Roadmap
  • System Design
  • High Level Design
  • Low Level Design
  • UML Diagrams
  • Interview Guide
  • Design Patterns
  • OOAD
  • System Design Bootcamp
  • Interview Questions
  • Inteview Preparation
  • Competitive Programming
  • Top DS or Algo for CP
  • Company-Wise Recruitment Process
  • Company-Wise Preparation
  • Aptitude Preparation
  • Puzzles
  • School Subjects
  • Mathematics
  • Physics
  • Chemistry
  • Biology
  • Social Science
  • English Grammar
  • Commerce
  • World GK
  • GeeksforGeeks Videos
  • DSA
  • Python
  • Java
  • C++
  • Web Development
  • Data Science
  • CS Subjects
@GeeksforGeeks, Sanchhaya Education Private Limited, All rights reserved
We use cookies to ensure you have the best browsing experience on our website. By using our site, you acknowledge that you have read and understood our Cookie Policy & Privacy Policy
Lightbox
Improvement
Suggest Changes
Help us improve. Share your suggestions to enhance the article. Contribute your expertise and make a difference in the GeeksforGeeks portal.
geeksforgeeks-suggest-icon
Create Improvement
Enhance the article with your expertise. Contribute to the GeeksforGeeks community and help create better learning resources for all.
geeksforgeeks-improvement-icon
Suggest Changes
min 4 words, max Words Limit:1000

Thank You!

Your suggestions are valuable to us.

What kind of Experience do you want to share?

Interview Experiences
Admission Experiences
Career Journeys
Work Experiences
Campus Experiences
Competitive Exam Experiences