Note: If a, a + d, a + 2d, a + 3d, . . . is arithmetic sequence then a + (a + d) + (a + 2d) + (a + 3d) + . . . is arithmetic series.
Note: The terms of an arithmetic sequence look like this: a, a + d, a + 2d, a + 3d, . . . , a + (n − 1)d
The sum of the first n terms of this sequence, Sn, can be written as:
Sn = a + (a + d) + (a + 2d) + (a + 3d) + . . . +[a + (n − 1)d]
⇒ Sn = [a+(n−1)d] + [a+(n−2)d] + . . . + a
Now, add these two expressions for Sn term by term:
2Sn = (a+[a+(n−1)d]) + ((a+d)+[a+(n−2)d]) + . . . + ([a+(n−1)d]+a)
Each pair of terms in parentheses sums to the same value i.e., a+[a+(n−1)d] = 2a+(n−1)d
Thus, 2Sn = n ⋅ [2a + (n − 1)d]
Sn = (n/2) ⋅ [2a + (n − 1)d]