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JavaScript Program to Check if a Character is Vowel or Not

JavaScript - String Contains Only Alphabetic Characters or Not

Last Updated : 16 Nov, 2024

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Here are several methods to check if a string contains only alphabetic characters in JavaScript

Using Regular Expression (/^[A-Za-z]+$/) - Most USed

The most common approach is to use a regular expression to match only alphabetic characters (both uppercase and lowercase).

JavaScript

let s = "HelloWorld"; let isAlphabetic = /^[A-Za-z]+$/.test(s); console.log(isAlphabetic);

Output

true

This checks if the string contains only the letters A-Z and a-z. It will return true if all characters are alphabetic and false otherwise.

Using every() Method with Regular Expression

The every() method can be used with a regular expression to iterate over each character and verify it matches [A-Za-z].

JavaScript

let s = "HelloWorld"; let isAlphabetic = Array.from(s).every((char) =>     /[A-Za-z]/.test(char)); console.log(isAlphabetic);

Output

true

This approach works well for checking each character individually against the pattern.

Using for Loop with charCodeAt()

Using a for loop, you can check each character for alphabets without regular expressions.

JavaScript

let s = "HelloWorld"; let isAlphabetic = true;  for (let i = 0; i < s.length; i++) {     let code = s.charCodeAt(i);     if (!(code >= 65 && code <= 90) && !(code >= 97 && code <= 122)) {         isAlphabetic = false;         break;     } } console.log(isAlphabetic);

Output

true

Using every() with charCodeAt()

This method uses Array.from() to split the string into characters, then checks each one’s ASCII code.

JavaScript

let s = "HelloWorld"; let isAlphabetic = Array.from(s).every(char => {     let code = char.charCodeAt(0);     return (code >= 65 && code <= 90) || (code >= 97 && code <= 122); }); console.log(isAlphabetic);

Output

true

Using isNaN() Function

To check if each character is non-numeric, you can use isNaN() along with checking for alphabetic ranges.

JavaScript

let s = "HelloWorld"; let isAlphabetic = Array.from(s).every(     (char) => isNaN(char) && /[A-Za-z]/.test(char) ); console.log(isAlphabetic);

Output

true

Using filter() with match()

The filter() method can filter out non-alphabetic characters by checking each one with match(), and the length of the result should match the original string length if all are alphabetic.

JavaScript

let s = "HelloWorld"; let isAlphabetic =     s.split("").filter((char) =>          char.match(/[A-Za-z]/)).length === s.length; console.log(isAlphabetic);

Output

true

The regular expression (/^[A-Za-z]+$/) remains the most efficient approach. However, methods like every() with charCodeAt() or a for loop offer flexibility for character-by-character validation.

JavaScript Program to Check if a Character is Vowel or Not

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