How to skip only first element of List in Scala

Last Updated : 17 Apr, 2019

In Scala, list is defined under scala.collection.immutable package. A list is a collection of same type elements which contains immutable data. Let's see how to print the element of given List, by skipping the first item in Scala. List in Scala contains many suitable methods to perform simple operations like head(), tail(), isEmpty(). Coming to list, tail() method is used to skip the first element of the list. below are examples to skip only first element of List. Example :

scala

// Scala program to skip only first element of List import scala.collection.immutable._  // Creating object  object GFGobject {      // Main method      def main(args:Array[String])      {          // Creating and initializing immutable lists          val mylist: List[String] = List("Geeks", "For", "geeks", "is",                                           "a", "fabulous", "portal")           println(mylist.tail)       } }

Output:

  List(For, geeks, is, a, fabulous, portal)

Example :

scala

// Scala program to skip only first element of List import scala.collection.immutable._  // Creating object  object GFG  {      // Main method      def main(args:Array[String])      {          // range from 10 to 19         val myList = List.range(10, 19)         println(myList)           println("Using tail() method: " + myList.tail)     }  }

Output:

  List(10, 11, 12, 13, 14, 15, 16, 17, 18)  Using tail() method: List(11, 12, 13, 14, 15, 16, 17, 18)

How to access list elements in Scala?

Shivam_k

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In Scala, list is defined under scala.collection.immutable package. A list is a collection of same type elements which contains immutable data. Let's see how to get the first element of given List in Scala.List in Scala contains many suitable methods to perform simple operations like head(), tail(),

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How to skip only first element of List in Scala

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