All about Bit Manipulation

Last Updated : 18 Apr, 2023

Bit Manipulation is a technique used in a variety of problems to get the solution in an optimized way. This technique is very effective from a Competitive Programming point of view. It is all about Bitwise Operators which directly works upon binary numbers or bits of numbers that help the implementation fast. Below are the Bitwise Operators that are used:

Bitwise AND (&)
Bitwise OR (|)
Bitwise XOR (^)
Bitwise NOT (!)

All data in computer programs are internally stored as bits, i.e., as numbers 0 and 1.

Bit representation

In programming, an n-bit integer is internally stored as a binary number that consists of n bits. For example, the C++ type int is a 32-bit type, which means that every int number consists of 32 bits.

The int number 43 = 00000000000000000000000000101011

The bits in the representation are indexed from right to left. To convert a bit representation b_k ···b₂ b₁ b₀ into a number, we can use the formula
b_k2^k +...+ b₂2² + b₁2¹ + b₀2⁰.

E.g., 1·2⁵+1·2³ +1·2¹ +1·2⁰ = 43.

The bit representation of a number is either signed or unsigned.
Usually, a signed representation is used, which means that both negative and positive numbers can be represented.
A signed variable of n bits can contain any integer between -2^n-1 and 2^n-1 - 1
The int type in C++ is a signed type, so an int variable can contain any integer between -2³¹ and 2³¹ - 1.

The first bit in a signed representation is the sign of the number, 0 for non-negative numbers and 1 for negative numbers and the remaining n−1 bits contain the magnitude of the number.

Two’s complement is used, which means that the opposite number of a number is calculated by first inverting all the bits in the number, and then increasing the number by one.
The bit representation of the int number −43 is 11111111111111111111111111010101
In an unsigned representation, only non-negative numbers can be used, but the upper bound for the values is larger.
An unsigned variable of n bits can contain any integer between 0 and 2ⁿ −1.

In C++, an unsigned int variable can contain any integer between 0 and 2³² −1.
There is a connection between the representations:
A signed number −x equals an unsigned number 2ⁿ − x.
For example, the following pseudo-code snippet shows that the signed number
x = −43 equals the unsigned number y = 2³² −43:

the pseudo-code snippet shows that the signed number

If a number is larger than the upper bound of the bit representation, the number will overflow. In a signed representation, the next number after 2^n-1 - 1 is -2^n-1, and in an unsigned representation, the next number after 2ⁿ -1 is 0. For example, consider the following pseudo-code snippet:

Initially, the value of x is 2³¹ −1. This is the largest value that can be stored in an int variable, so the next number after 2³¹ −1 is −2³¹ .

Learn more about Bitwise Operators in this article. Below are some common bit operations that are frequently used in programming:

Bitwise Operations:

Below is the table to illustrate the result when the operation is performed using Bitwise Operators. Here 0s or 1s mean a sequence of 0 or 1 respectively.

Operators	Operations	Result
XOR	X ^ 0s	X
XOR	X ^ 1s	~X
XOR	X ^ X	0
AND	X & 0s	0
AND	X & 1s	X
AND	X & X	X
OR	X \| 0s	X
OR	X \| 1s	1s
OR	X \| X	X

Get Bit:

This method is used to find the bit at a particular position(say i) of the given number N. The idea is to find the Bitwise AND of the given number and 2i that can be represented as (1 << i). If the value return is 1 then the bit at the ith position is set. Otherwise, it is unset.

Below is the pseudo-code for the same:

C++

// Function to get the bit at the // ith position bool getBit(int num, int i) {     // Return true if the bit is     // set. Otherwise return false     return ((num & (1 << i)) != 0); }

Java

// Function to get the bit at the // ith position static boolean getBit(int num, int i) {     // Return true if the bit is     // set. Otherwise return false     return ((num & (1 << i)) != 0); }  // This code is contributed by rishavmahato348.

Python3

# Function to get the bit at the # ith position def getBit(num, i):        # Return true if the bit is     # set. Otherwise return false     return ((num & (1 << i)) != 0)      # This code is contributed by shivani

// Function to get the bit at the // ith position static bool getBit(int num, int i) {     // Return true if the bit is     // set. Otherwise return false     return ((num & (1 << i)) != 0); }  // This code is contributed by subhammahato348.

JavaScript

<script>  // Function to get the bit at the // ith position function getBit(num, i) {          // Return true if the bit is     // set. Otherwise return false     return ((num & (1 << i)) != 0); }  // This code is contributed by Ankita saini  </script>

Set Bit:

This method is used to set the bit at a particular position(say i) of the given number N. The idea is to update the value of the given number N to the Bitwise OR of the given number N and 2i that can be represented as (1 << i). If the value return is 1 then the bit at the ith position is set. Otherwise, it is unset.

Below is the pseudo-code for the same:

C++

// Function to set the ith bit of the // given number num int setBit(int num, int i) {     // Sets the ith bit and return     // the updated value     return num | (1 << i); }

Java

// Function to set the ith bit of the // given number num static int setBit(int num, int i) {     // Sets the ith bit and return     // the updated value     return num | (1 << i); }  // This code is contributed by subhammahato348

Python3

# Function to set the ith bit of the # given number num def setBit(num, i):          # Sets the ith bit and return     # the updated value     return num | (1 << i)  # This code is contributed by kirti

// Function to set the ith bit of the // given number num static int setBit(int num, int i) {     // Sets the ith bit and return     // the updated value     return num | (1 << i); }

JavaScript

// Function to set the ith bit of the // given number num function setBit(num, i) {     // Sets the ith bit and return     // the updated value     return num | (1 << i); }

Clear Bit:

This method is used to clear the bit at a particular position(say i) of the given number N. The idea is to update the value of the given number N to the Bitwise AND of the given number N and the compliment of 2i that can be represented as ~(1 << i). If the value return is 1 then the bit at the ith position is set. Otherwise, it is unset.

Below is the pseudo-code for the same:

C++

// Function to clear the ith bit of // the given number num int clearBit(int num, int i) {      // Create the mask for the ith     // bit unset     int mask = ~(1 << i);      // Return the updated value     return num & mask; }

Java

// Function to clear the ith bit of // the given number num static int clearBit(int num, int i) {      // Create the mask for the ith     // bit unset     int mask = ~(1 << i);      // Return the updated value     return num & mask; }  // This code is contributed by subham348

Python3

# Function to clear the ith bit of # the given number num  def clearBit(num, i):      # Create the mask for the ith     # bit unset     mask = ~(1 << i)      # Return the updated value     return num & mask  # This code is contributed by subhammahato348

// Function to clear the ith bit of // the given number num static int clearBit(int num, int i) {      // Create the mask for the ith     // bit unset     int mask = ~(1 << i);      // Return the updated value     return num & mask; }  // This code is contributed by Ankita Saini

JavaScript

// Function to clear the ith bit of // the given number num function clearBit(num, i) {      // Create the mask for the ith     // bit unset     let mask = ~(1 << i);      // Return the updated value     return num & mask; }  // This code is contributed by souravmahato348.

Below is the program that implements the above functionalities:

C++

// C++ program to implement all the // above functionalities  #include <bits/stdc++.h> using namespace std;  // Function to get the bit at the // ith position bool getBit(int num, int i) {     // Return true if the ith bit is     // set. Otherwise return false     return ((num & (1 << i)) != 0); }  // Function to set the ith bit of the // given number num int setBit(int num, int i) {     // Sets the ith bit and return     // the updated value     return num | (1 << i); }  // Function to clear the ith bit of // the given number num int clearBit(int num, int i) {      // Create the mask for the ith     // bit unset     int mask = ~(1 << i);      // Return the updated value     return num & mask; }  // Driver Code int main() {     // Given number N     int N = 70;      cout << "The bit at the 3rd position from LSB is: "          << (getBit(N, 3) ? '1' : '0')          << endl;      cout << "The value of the given number "          << "after setting the bit at "          << "LSB is: "          << setBit(N, 0) << endl;      cout << "The value of the given number "          << "after clearing the bit at "          << "LSB is: "          << clearBit(N, 0) << endl;      return 0; }

Java

// Java program to implement all the // above functionalities import java.io.*;  class GFG{  // Function to get the bit at the // ith position static boolean getBit(int num, int i) {          // Return true if the ith bit is     // set. Otherwise return false     return ((num & (1 << i)) != 0); }  // Function to set the ith bit of the // given number num static int setBit(int num, int i) {          // Sets the ith bit and return     // the updated value     return num | (1 << i); }  // Function to clear the ith bit of // the given number num static int clearBit(int num, int i) {          // Create the mask for the ith     // bit unset     int mask = ~(1 << i);      // Return the updated value     return num & mask; }  // Driver Code public static void main(String[] args) {          // Given number N     int N = 70;      System.out.println("The bit at the 3rd position from LSB is: " +                         (getBit(N, 3) ? '1' : '0'));      System.out.println("The value of the given number " +                         "after setting the bit at " +                         "LSB is: " + setBit(N, 0));      System.out.println("The value of the given number " +                         "after clearing the bit at " +                         "LSB is: " + clearBit(N, 0)); } }  // This code is contributed by souravmahato348

Python

# Python program to implement all the # above functionalities # Function to get the bit at the # ith position def getBit( num,  i):      # Return true if the ith bit is     # set. Otherwise return false     return ((num & (1 << i)) != 0)  # Function to set the ith bit of the # given number num def setBit( num,  i):      # Sets the ith bit and return     # the updated value     return num | (1 << i)  # Function to clear the ith bit of # the given number num def clearBit( num,  i):          # Create the mask for the ith     # bit unset     mask = ~(1 << i)          # Return the updated value     return num & mask  # Driver Code # Given number N N = 70 print"The bit at the 3rd position from LSB is: " , 1 if (getBit(N, 3)) else '0'  print"The value of the given number" , "after setting the bit at","LSB is: " , setBit(N, 0)  print"The value of the given number" , "after clearing the bit at","LSB is: " , clearBit(N, 0)  # This code is contributed by shivanisinghss2110

// C# program to implement all the // above functionalities using System;  class GFG {      // Function to get the bit at the     // ith position     static bool getBit(int num, int i)     {          // Return true if the ith bit is         // set. Otherwise return false         return ((num & (1 << i)) != 0);     }      // Function to set the ith bit of the     // given number num     static int setBit(int num, int i)     {          // Sets the ith bit and return         // the updated value         return num | (1 << i);     }      // Function to clear the ith bit of     // the given number num     static int clearBit(int num, int i)     {          // Create the mask for the ith         // bit unset         int mask = ~(1 << i);          // Return the updated value         return num & mask;     }      // Driver Code     public static void Main()     {          // Given number N         int N = 70;          Console.WriteLine("The bit at the 3rd position form LSB is: "                           + (getBit(N, 3) ? '1' : '0'));          Console.WriteLine("The value of the given number "                           + "after setting the bit at "                           + "LSB is: " + setBit(N, 0));          Console.WriteLine("The value of the given number "                           + "after clearing the bit at "                           + "LSB is: " + clearBit(N, 0));     } }  // This code is contributed by rishavmahato348.

JavaScript

<script>  // Javascript program to implement all // the above functionalities  // Function to get the bit at the // ith position function getBit(num, i) {          // Return true if the ith bit is     // set. Otherwise return false     return ((num & (1 << i)) != 0); }  // Function to set the ith bit of the // given number num function setBit(num, i) {          // Sets the ith bit and return     // the updated value     return num | (1 << i); }  // Function to clear the ith bit of // the given number num function clearBit(num, i) {      // Create the mask for the ith     // bit unset     let mask = ~(1 << i);      // Return the updated value     return num & mask; }  // Driver code  // Given number N let N = 70;  document.write("The bit at the 3rd position from LSB is: " +                (getBit(N, 3) ? '1' : '0') + "</br>");  document.write("The value of the given number " +                 "after setting the bit at " +                 "LSB is: " + setBit(N, 0) + "</br>");  document.write("The value of the given number " +                 "after clearing the bit at " +                 "LSB is: " + clearBit(N, 0) + "</br>");                 // This code is contributed by divyeshrabadiya07  </script>

Output

The bit at the 3rd position from LSB is: 0 The value of the given number after setting the bit at LSB is: 71 The value of the given number after clearing the bit at LSB is: 70

Time Complexity: O(1)
Auxiliary Space: O(1)

Application of Bitwise Operator

Bitwise operations are prominent in embedded systems, control systems, etc where memory(data transmission/data points) is still an issue.
They are also useful in networking where it is important to reduce the amount of data, so booleans are packed together. Packing them together and taking them apart use bitwise operations and shift instructions.
Bitwise operations are also heavily used in the compression and encryption of data.
Useful in graphics programming, older GUIs are heavily dependent on bitwise operations like XOR(^) for selection highlighting and other overlays.

What is Endianness? Big-Endian & Little-Endian

swagami6

Improve

Article Tags :

Practice Tags :

Bit Magic

All about Bit Manipulation

Get Bit:

Set Bit:

Clear Bit:

Similar Reads

Easy Problems on Bit Manipulations and Bitwise Algorithms