C++ Program to Maximize elements using another array

Last Updated : 24 Mar, 2023

Given two arrays with size n, maximize the first array by using the elements from the second array such that the new array formed contains n greatest but unique elements of both the arrays giving the second array priority (All elements of second array appear before first array). The order of appearance of elements is kept same in output as in input.
Examples:

Input : arr1[] = {2, 4, 3}
arr2[] = {5, 6, 1}
Output : 5 6 4
As 5, 6 and 4 are maximum elements from two arrays giving second array higher priority. Order of elements is same in output as in input.
Input : arr1[] = {7, 4, 8, 0, 1}
arr2[] = {9, 7, 2, 3, 6}
Output : 9 7 6 4 8

Approach : We create an auxiliary array of size 2*n and store the elements of 2nd array in auxiliary array, and then we will store elements of 1st array in it. After that we will sort auxiliary array in decreasing order. To keep the order of elements according to input arrays we will use hash table. We will store 1st n largest unique elements of auxiliary array in hash table. Now we traverse the second array and store that elements of second array in auxiliary array that are present in hash table. Similarly we will traverse first array and store the elements that are present in hash table. In this way we get n unique and largest elements from both the arrays in auxiliary array while keeping the order of appearance of elements same.

Below is the implementation of above approach :

C++

// C++ program to print the maximum elements // giving second array higher priority #include <bits/stdc++.h> using namespace std;  // Compare function used to sort array  // in decreasing order bool compare(int a, int b) {     return a > b; }  // Function to maximize array elements void maximizeArray(int arr1[], int arr2[],                                    int n) {     // auxiliary array arr3 to store      // elements of arr1 & arr2     int arr3[2*n], k = 0;     for (int i = 0; i < n; i++)          arr3[k++] = arr1[i];     for (int i = 0; i < n; i++)         arr3[k++] = arr2[i];      // hash table to store n largest     // unique elements     unordered_set<int> hash;      // sorting arr3 in decreasing order     sort(arr3, arr3 + 2 * n, compare);      // finding n largest unique elements     // from arr3 and storing in hash     int i = 0;     while (hash.size() != n) {          // if arr3 element not present in hash,         // then store this element in hash         if (hash.find(arr3[i]) == hash.end())              hash.insert(arr3[i]);                  i++;     }      // store that elements of arr2 in arr3     // that are present in hash     k = 0;     for (int i = 0; i < n; i++) {          // if arr2 element is present in hash,         // store it in arr3         if (hash.find(arr2[i]) != hash.end()) {             arr3[k++] = arr2[i];             hash.erase(arr2[i]);         }     }      // store that elements of arr1 in arr3     // that are present in hash     for (int i = 0; i < n; i++) {          // if arr1 element is present in hash,         // store it in arr3         if (hash.find(arr1[i]) != hash.end()) {             arr3[k++] = arr1[i];             hash.erase(arr1[i]);         }     }      // copying 1st n elements of arr3 to arr1     for (int i = 0; i < n; i++)          arr1[i] = arr3[i];     }  // Function to print array elements void printArray(int arr[], int n) {     for (int i = 0; i < n; i++)          cout << arr[i] << " ";         cout << endl; }  // Driver Code int main() {     int array1[] = { 7, 4, 8, 0, 1 };     int array2[] = { 9, 7, 2, 3, 6 };     int size = sizeof(array1) / sizeof(array1[0]);     maximizeArray(array1, array2, size);     printArray(array1, size); }

Output:

9 7 6 4 8

Time complexity: O(n * log n).
Space complexity: O(n) as array and set has been created.

Please refer complete article on Maximize elements using another array for more details!

C++ Program to Find the Minimum and Maximum Element of an Array

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C++ Program to Maximize elements using another array

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