Count strings having sum of ASCII values of characters equal to a Prime or Armstrong Number

Last Updated : 08 Feb, 2024

Given an array arr[] of size N containing strings, the task is to count the number of strings having the sum of ASCII (American Standard Code for Information Interchange) values of characters equal to an Armstrong Number number or a Prime Number.

Examples:

Input: arr[] = {“hello”, “nace”}
Output:
Number of Armstrong Strings are: 1
Number of Prime Strings are: 0
Explanation: Sum of ASCII values of characters of each string is: {532, 407}, out of which 407 is an Armstrong Number, and none of them is a Prime Number.
Hence, the armstrong valued string is “nace”.

Input: arr[] = {“geeksforgeeks”, “a”, “computer”, “science”, “portal”, “for”, “geeks”}
Output:
Number of Armstrong Strings are: 0
Number of Prime Strings are: 2
Explanation: Sum of ASCII values of characters of each string is: {1381, 97, 879, 730, 658, 327, 527}, out of which 1381 and 97 are Prime Numbers, and none of them is an Armstrong Number.
Hence, prime valued strings are “geeksforgeeks” and “a”.

Approach: This problem can be solved by calculating the ASCII value of each string. Follow the steps below to solve this problem:

Initialize two variables, countPrime and countArmstrong as 0, to store the count of Prime and Armstrong valued strings.
Iterate over the range of indices [0, N – 1] using a variable, say i and perform the following steps:
- Store the sum of ASCII values of characters of the current string arr[i] in a variable, say val.
- If the number val is an Armstrong Number, increment countArmstrong by 1.
- If the number val is a Prime Number, increment countPrime by 1.
Print the values of countPrime and countArmstrong as the result.

Below is the implementation of the above approach:

C++

   // C++ program for the above approach
#include <bits/stdc++.h>
using namespace std;
 
// Function to check if a
// number is prime number
bool isPrime(int num)
{
     
    // Define a flag variable
    bool flag = false;
 
    if (num > 1)
    {
         
        // Check for factors of num
        for(int i = 2; i < num; i++)
        {
             
            // If factor is found,
            // set flag to True and
            // break out of loop
            if ((num % i) == 0)
            {
                flag = true;
                break;
            }
        }
    }
 
    // Check if flag is True
    if (flag)
        return false;
    else
        return true;
}
 
// Function to calculate
// order of the number x
int order(int x)
{
    int n = 0;
    while (x != 0)
    {
        n = n + 1;
        x = x / 10;
    }
    return n;
}
 
// Function to check whether the given
// number is Armstrong number or not
bool isArmstrong(int x)
{
    int n = order(x);
    int temp = x;
    int sum1 = 0;
 
    while (temp != 0)
    {
        int r = temp % 10;
        sum1 = sum1 + pow(r, n);
        temp = temp / 10;
    }
     
    // If the condition satisfies
    return (sum1 == x);
}
 
// Function to count
// Armstrong valued strings
int count_armstrong(vector<string> li)
{
     
    // Stores the count of
    // Armstrong valued strings
    int c = 0;
 
    // Iterate over the list
    for(string ele : li)
    {
         
        // Store the value
        // of the string
        int val = 0;
 
        // Find value of the string
        for(char che:ele)
            val += che;
 
        // Check if it an Armstrong number
        if (isArmstrong(val))
            c += 1;
    }
    return c;
}
 
// Function to count
// prime valued strings
int count_prime(vector<string> li)
{
     
    // Store the count of
    // prime valued strings
    int c = 0;
 
    // Iterate over the list
    for(string ele:li)
    {
         
        // Store the value
        // of the string
        int val = 0;
 
        // Find value of the string
        for(char che : ele)
            val += che;
 
        // Check if it
        // is a Prime Number
        if (isPrime(val))
            c += 1;
    }
    return c;
}
 
// Driver code
int main()
{
    vector<string> arr = { "geeksforgeeks", "a", "computer", 
                           "science", "portal", "for", "geeks"};
     
    // Function Call
    cout << "Number of Armstrong Strings are: "
         << count_armstrong(arr) << endl;
    cout << "Number of Prime Strings are: "
         << count_prime(arr) << endl;
}
 
// This code is contributed by mohit kumar 29
 
  

Java

   // Java program for the above approach
import java.io.*;
 
class GFG {
     
    // Function to check if a
    // number is prime number
    static boolean isPrime(int num)
    {
  
        // Define a flag variable
        boolean flag = false;
  
        if (num > 1) {
  
            // Check for factors of num
            for (int i = 2; i < num; i++) {
  
                // If factor is found,
                // set flag to True and
                // break out of loop
                if ((num % i) == 0) {
                    flag = true;
                    break;
                }
            }
        }
  
        // Check if flag is True
        if (flag)
            return false;
        else
            return true;
    }
  
    // Function to calculate
    // order of the number x
    static int order(int x)
    {
        int n = 0;
        while (x != 0) {
            n = n + 1;
            x = x / 10;
        }
        return n;
    }
  
    // Function to check whether the given
    // number is Armstrong number or not
    static boolean isArmstrong(int x)
    {
        int n = order(x);
        int temp = x;
        int sum1 = 0;
  
        while (temp != 0) {
            int r = temp % 10;
            sum1 = sum1 + (int)(Math.pow(r, n));
            temp = temp / 10;
        }
  
        // If the condition satisfies
        return (sum1 == x);
    }
  
    // Function to count
    // Armstrong valued strings
    static int count_armstrong(String[] li)
    {
  
        // Stores the count of
        // Armstrong valued strings
        int c = 0;
  
        // Iterate over the list
        for(String ele : li)
        {
  
            // Store the value
            // of the string
            int val = 0;
  
            // Find value of the string
            for(char che : ele.toCharArray()) val += che;
  
            // Check if it an Armstrong number
            if (isArmstrong(val))
                c += 1;
        }
        return c;
    }
  
    // Function to count
    // prime valued strings
    static int count_prime(String[] li)
    {
  
        // Store the count of
        // prime valued strings
        int c = 0;
  
        // Iterate over the list
        for(String ele : li)
        {
  
            // Store the value
            // of the string
            int val = 0;
  
            // Find value of the string
            for(char che : ele.toCharArray()) val += che;
  
            // Check if it
            // is a Prime Number
            if (isPrime(val))
                c += 1;
        }
        return c;
    }
  
    // Driver code
     
    public static void main (String[] args) {
        String[] arr
            = { "geeksforgeeks", "a",      "computer",
                "science",       "portal", "for",
                "geeks" };
  
        // Function Call
        System.out.println(
            "Number of Armstrong Strings are: "
            + count_armstrong(arr));
        System.out.println("Number of Prime Strings are: "
                          + count_prime(arr));
    }
}
 
// This code is contributed by patel2127.
 
  

Python3

   # Python program for the above approach
 
# Function to check if a
# number is prime number
def isPrime(num):
 
    # Define a flag variable
    flag = False
 
    if num > 1:
 
        # Check for factors of num
        for i in range(2, num):
 
            # If factor is found,
            # set flag to True and
            # break out of loop
            if (num % i) == 0:
                flag = True
                break
 
    # Check if flag is True
    if flag:
        return False
    else:
        return True
 
# Function to calculate
# order of the number x
def order(x):
    n = 0
    while (x != 0):
        n = n + 1
        x = x // 10
    return n
 
# Function to check whether the given
# number is Armstrong number or not
def isArmstrong(x):
    n = order(x)
    temp = x
    sum1 = 0
 
    while (temp != 0):
 
        r = temp % 10
        sum1 = sum1 + r**n
        temp = temp // 10
 
    # If the condition satisfies
    return (sum1 == x)
 
# Function to count
# Armstrong valued strings
def count_armstrong(li):
 
    # Stores the count of
    # Armstrong valued strings
    c = 0
 
    # Iterate over the list
    for ele in li:
 
        # Store the value 
        # of the string
        val = 0
         
        # Find value of the string
        for che in ele:
            val += ord(che)
             
        # Check if it an Armstrong number
        if isArmstrong(val):
            c += 1
    return c
 
# Function to count
# prime valued strings
def count_prime(li):
     
    # Store the count of
    # prime valued strings
    c = 0
     
    # Iterate over the list
    for ele in li:
       
        # Store the value
        # of the string
        val = 0
         
        # Find value of the string
        for che in ele:
            val += ord(che)
             
        # Check if it
        # is a Prime Number
        if isPrime(val):
            c += 1
    return c
 
 
# Driver code
arr = ["geeksforgeeks", "a", "computer", 
       "science", "portal", "for", "geeks"]
 
# Function Call
print("Number of Armstrong Strings are:", count_armstrong(arr))
print("Number of Prime Strings are:", count_prime(arr))
 
  

C#

   // C# program for the above approach
using System;
using System.Collections.Generic;
class GFG 
{
   
    // Function to check if a
    // number is prime number
    static bool isPrime(int num)
    {
 
        // Define a flag variable
        bool flag = false;
 
        if (num > 1) {
 
            // Check for factors of num
            for (int i = 2; i < num; i++) {
 
                // If factor is found,
                // set flag to True and
                // break out of loop
                if ((num % i) == 0) {
                    flag = true;
                    break;
                }
            }
        }
 
        // Check if flag is True
        if (flag)
            return false;
        else
            return true;
    }
 
    // Function to calculate
    // order of the number x
    static int order(int x)
    {
        int n = 0;
        while (x != 0) {
            n = n + 1;
            x = x / 10;
        }
        return n;
    }
 
    // Function to check whether the given
    // number is Armstrong number or not
    static bool isArmstrong(int x)
    {
        int n = order(x);
        int temp = x;
        int sum1 = 0;
 
        while (temp != 0) {
            int r = temp % 10;
            sum1 = sum1 + (int)(Math.Pow(r, n));
            temp = temp / 10;
        }
 
        // If the condition satisfies
        return (sum1 == x);
    }
 
    // Function to count
    // Armstrong valued strings
    static int count_armstrong(string[] li)
    {
 
        // Stores the count of
        // Armstrong valued strings
        int c = 0;
 
        // Iterate over the list
        foreach(string ele in li)
        {
 
            // Store the value
            // of the string
            int val = 0;
 
            // Find value of the string
            foreach(char che in ele) val += che;
 
            // Check if it an Armstrong number
            if (isArmstrong(val))
                c += 1;
        }
        return c;
    }
 
    // Function to count
    // prime valued strings
    static int count_prime(string[] li)
    {
 
        // Store the count of
        // prime valued strings
        int c = 0;
 
        // Iterate over the list
        foreach(string ele in li)
        {
 
            // Store the value
            // of the string
            int val = 0;
 
            // Find value of the string
            foreach(char che in ele) val += che;
 
            // Check if it
            // is a Prime Number
            if (isPrime(val))
                c += 1;
        }
        return c;
    }
 
    // Driver code
    public static void Main()
    {
        string[] arr
            = { "geeksforgeeks", "a",      "computer",
                "science",       "portal", "for",
                "geeks" };
 
        // Function Call
        Console.WriteLine(
            "Number of Armstrong Strings are: "
            + count_armstrong(arr));
        Console.WriteLine("Number of Prime Strings are: "
                          + count_prime(arr));
    }
}
 
// This code is contributed by ukasp.
 
  

Javascript

   <script>
 
// JavaScript program for the above approach
 
// Function to check if a
// number is prime number
function isPrime(num) {
 
    // Define a flag variable
    let flag = false;
 
    if (num > 1) {
 
        // Check for factors of num
        for (let i = 2; i < num; i++) {
 
            // If factor is found,
            // set flag to True and
            // break out of loop
            if ((num % i) == 0) {
                flag = true;
                break;
            }
        }
    }
 
    // Check if flag is True
    if (flag)
        return false;
    else
        return true;
}
 
// Function to calculate
// order of the number x
function order(x) {
    let n = 0;
    while (x != 0) {
        n = n + 1;
        x = x / 10;
    }
    return n;
}
 
// Function to check whether the given
// number is Armstrong number or not
function isArmstrong(x) {
    let n = order(x);
    let temp = x;
    let sum1 = 0;
 
    while (temp != 0) {
        let r = temp % 10;
        sum1 = sum1 + Math.pow(r, n);
        temp = temp / 10;
    }
 
    // If the condition satisfies
    return (sum1 == x);
}
 
// Function to count
// Armstrong valued strings
function count_armstrong(li) {
 
    // Stores the count of
    // Armstrong valued strings
    let c = 0;
 
    // Iterate over the list
    for (let ele of li) {
 
        // Store the value
        // of the string
        let val = 0;
 
        // Find value of the string
        for (let che of ele)
            val += che.charCodeAt(0);
 
        // Check if it an Armstrong number
        if (isArmstrong(val))
            c += 1;
    }
    return c;
}
 
// Function to count
// prime valued strings
function count_prime(li) {
 
    // Store the count of
    // prime valued strings
    let c = 0;
 
    // Iterate over the list
    for (let ele of li) {
 
        // Store the value
        // of the string
        let val = 0;
 
        // Find value of the string
        for (let che of ele)
            val += che.charCodeAt(0);
 
        // Check if it
        // is a Prime Number
        if (isPrime(val))
            c += 1;
    }
    return c;
}
 
// Driver code
 
let arr = ["geeksforgeeks", "a", "computer",
    "science", "portal", "for", "geeks"];
 
// Function Call
document.write("Number of Armstrong Strings are: "
    + count_armstrong(arr) + "<br>");
document.write("Number of Prime Strings are: "
    + count_prime(arr) + "<br>");
 
 
// This code is contributed by gfgking
 
</script>
 
  

Output

Number of Armstrong Strings are: 0 Number of Prime Strings are: 2

Time Complexity: O(N*M), where M is the length of the longest string in the array arr[]
Auxiliary Space: O(1)

Make all characters of a string same by minimum number of increments or decrements of ASCII values of characters

santhoshcharan

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Practice Tags :

Count strings having sum of ASCII values of characters equal to a Prime or Armstrong Number

C++

Java

Python3

C#

Javascript

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