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Connected Components in an Undirected Graph
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Connected Components in an Undirected Graph

Last Updated : 16 Apr, 2025
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Given an undirected graph, the task is to return all the connected components in any order. 

Examples:

Input: Consider the following graph

Example of an undirected graph
Example of an undirected graph

Output: [[0, 1, 2], [3, 4]]
Explanation: There are 2 different connected components.
They are {0, 1, 2} and {3, 4}.

Table of Content

  • Approach 1: Using Depth first search (DFS)
  • Approach 2: Using Disjoint Set Union (DSU)

Approach 1: Using Depth first search (DFS)

The main idea is to Use DFS to explore each node. If a node hasn’t been visited yet, start a DFS from it. All nodes reached during this traversal belong to the same connected component.

Step by Step implementation:

  • Create an adjacency list from the edge list.
  • Initialize a visited array and mark every node as unvisited initially.
  • Start from any unvisited node and perform a DFS. All nodes reachable from this node will belong to the same connected component.
  • Iterate over all nodes, and for each unvisited node, perform a DFS and store the result.
C++
#include <iostream> #include <vector> using namespace std;  // Function to build the adjacency list from edge list vector<vector<int>> buildGraph(int V, vector<vector<int>>& edges) {          vector<vector<int>> adj(V);      // Populate the adjacency list from the edge list     for (auto edge : edges) {         int u = edge[0];         int v = edge[1];          // Add both directions since the graph is undirected         adj[u].push_back(v);         adj[v].push_back(u);     }      return adj; }  // Function to perform DFS and collect all // nodes in the current connected component void dfs(int node, vector<vector<int>>& adj,          vector<bool>& vis, vector<int>& component) {          // Mark the current node as visited     vis[node] = true;      // Add the node to the current component     component.push_back(node);      // Traverse all unvisited neighbors     for (int neighbor : adj[node]) {         if (!vis[neighbor]) {             dfs(neighbor, adj, vis, component);         }     } }  // Function to find all connected components  // in an undirected graph vector<vector<int>> getComponents(int V, vector<vector<int>>& edges) {          // Create the graph using the adjacency list     vector<vector<int>> adj = buildGraph(V, edges);      // Initialize a visited array to keep track of visited nodes     vector<bool> vis(V, false);      // This will store all the connected components     vector<vector<int>> res;      // Iterate through all nodes     for (int i = 0; i < V; ++i) {         // If the node has not been visited, it's a new component         if (!vis[i]) {                          vector<int> component;              // Perform DFS to collect all nodes in this component             dfs(i, adj, vis, component);              // Add the component to the result list             res.push_back(component);         }     }      // Return the list of all connected components     return res; }  int main() {     // Number of nodes in the graph     int V = 5;      // Edge list representing the undirected graph as vector of vectors     vector<vector<int>> edges = {{0, 1}, {1, 2}, {3, 4}};      // Get all connected components using the countComponents function     vector<vector<int>> res = getComponents(V, edges);      for (const auto& comp : res) {                  for (int node : comp) {             cout << node << " ";         }         cout << "\n";     }      return 0; } 
Java
import java.util.*;  class GfG {          // Function to build the adjacency list from edge list     static ArrayList<ArrayList<Integer>> buildGraph(int V, int[][] edges) {                  ArrayList<ArrayList<Integer>> adj = new ArrayList<>();                  // Initialize the adjacency list with empty lists         for (int i = 0; i < V; i++) {             adj.add(new ArrayList<>());         }          // Populate the adjacency list from the edge list         for (int[] edge : edges) {             int u = edge[0];             int v = edge[1];              // Add both directions since the graph is undirected             adj.get(u).add(v);             adj.get(v).add(u);         }          return adj;     }      // Function to perform DFS and collect all      // nodes in the current connected component     static void dfs(int node, ArrayList<ArrayList<Integer>> adj,                           boolean[] vis, ArrayList<Integer> component) {                                        // Mark the current node as visited         vis[node] = true;          // Add the node to the current component         component.add(node);          // Traverse all unvisited neighbors         for (int neighbor : adj.get(node)) {             if (!vis[neighbor]) {                 dfs(neighbor, adj, vis, component);             }         }     }      // Function to find all connected components     // in an undirected graph     static ArrayList<ArrayList<Integer>> getComponents(int V, int[][] edges) {                  // Create the graph using the adjacency list         ArrayList<ArrayList<Integer>> adj = buildGraph(V, edges);          // Initialize a visited array to keep track of visited nodes         boolean[] vis = new boolean[V];          // This will store all the connected components         ArrayList<ArrayList<Integer>> res = new ArrayList<>();          // Iterate through all nodes         for (int i = 0; i < V; i++) {                          // If the node has not been visited, it's a new component             if (!vis[i]) {                 ArrayList<Integer> component = new ArrayList<>();                  // Perform DFS to collect all nodes in this component                 dfs(i, adj, vis, component);                  // Add the component to the result list                 res.add(component);             }         }          return res;     }      public static void main(String[] args) {                  // Number of nodes in the graph         int V = 5;          // Edge list representing the undirected graph as 2D array         int[][] edges = {             {0, 1},             {1, 2},             {3, 4}         };          // Get all connected components using the getComponents function         ArrayList<ArrayList<Integer>> res = getComponents(V, edges);          // Print each connected component         for (ArrayList<Integer> comp : res) {             for (int node : comp) {                 System.out.print(node + " ");             }             System.out.println();         }     } } 
Python
def buildGraph(n, edges):          adj = [[] for _ in range(V)]      # Populate the adjacency list from the edge list     for edge in edges:         u, v = edge[0], edge[1]          # Add both directions since the graph is undirected         adj[u].append(v)         adj[v].append(u)      return adj  def dfs(node, adj, vis, component):          # Mark the current node as visited     vis[node] = True      # Add the node to the current component     component.append(node)      # Traverse all unvisited neighbors     for neighbor in adj[node]:         if not vis[neighbor]:             dfs(neighbor, adj, vis, component)  def getComponents(V, edges):          # Create the graph using the adjacency list     adj = buildGraph(V, edges)      # Initialize a visited array to keep track of visited nodes     vis = [False] * V      # This will store all the connected components     res = []      # Iterate through all nodes     for i in range(V):                  # If the node has not been visited, it's a new component         if not vis[i]:             component = []              # Perform DFS to collect all nodes in this component             dfs(i, adj, vis, component)              # Add the component to the result list             res.append(component)      return res  if __name__ == "__main__":          # Number of nodes in the graph     V = 5      # Edge list representing the undirected graph as 2D array     edges = [         [0, 1],         [1, 2],         [3, 4]     ]      # Get all connected components using the countComponents function     res = getComponents(V, edges)      # Print each connected component     for comp in res:         print(" ".join(map(str, comp))) 
C#
using System; using System.Collections.Generic;  class GfG {          // Function to build the adjacency list from edge list      static List<List<int>> buildGraph(int V, int[,] edges) {                   List<List<int>> adj = new List<List<int>>();          // Initialize the adjacency list with empty lists for each node         for (int i = 0; i < V; i++) {             adj.Add(new List<int>());         }          // Populate the adjacency list from the edge list         for (int i = 0; i < edges.GetLength(0); i++) {             int u = edges[i, 0];             int v = edges[i, 1];              // Add both directions since the graph is undirected             adj[u].Add(v);             adj[v].Add(u);         }          return adj;     }      // Function to perform DFS and collect all     // nodes in the current connected component      static void dfs(int node, List<List<int>> adj,                           bool[] vis, List<int> component) {                                        // Mark the current node as visited         vis[node] = true;          // Add the node to the current component         component.Add(node);          // Traverse all unvisited neighbors         foreach (int neighbor in adj[node]) {             if (!vis[neighbor]) {                 dfs(neighbor, adj, vis, component);             }         }     }      // Function to find all connected components in an undirected graph     public static List<List<int>> getComponents(int V, int[,] edges) {                  // Create the graph using the adjacency list         List<List<int>> adj = buildGraph(V, edges);          // Initialize a visited array to keep track of visited nodes         bool[] vis = new bool[V];          // This will store all the connected components         List<List<int>> res = new List<List<int>>();          // Iterate through all nodes         for (int i = 0; i < V; i++) {                          // If the node has not been visited, it's a new component             if (!vis[i]) {                 List<int> component = new List<int>();                  // Perform DFS to collect all nodes in this component                 dfs(i, adj, vis, component);                  // Add the component to the result list                 res.Add(component);             }         }          return res;     }      static void Main() {                  // Number of nodes in the graph         int V = 5;          // Edge list representing the undirected graph as 2D array         int[,] edges = {             {0, 1},             {1, 2},             {3, 4}         };          // Get all connected components using the countComponents function         List<List<int>> res = getComponents(V, edges);          // Print each connected component         foreach (var comp in res) {             foreach (int node in comp) {                 Console.Write(node + " ");             }             Console.WriteLine();         }     } } 
JavaScript
// Function to build the adjacency list from the edge list function buildGraph(V, edges) {          let adj = Array.from({ length: V }, () => []);      // Populate the adjacency list from the edge list     for (let i = 0; i < edges.length; i++) {         let u = edges[i][0];         let v = edges[i][1];          // Add both directions since the graph is undirected         adj[u].push(v);         adj[v].push(u);     }      return adj; }  // Function to perform DFS and collect  // all nodes in the current connected component function dfs(node, adj, vis, component) {          // Mark the current node as visited     vis[node] = true;      // Add the node to the current component     component.push(node);      // Traverse all unvisited neighbors     for (let neighbor of adj[node]) {         if (!vis[neighbor]) {             dfs(neighbor, adj, vis, component);         }     } }  // Function to find all connected components in an undirected graph function getComponents(V, edges) {          // Create the graph using the adjacency list     let adj = buildGraph(V, edges);      // Initialize a visited array to keep track of visited nodes     let vis = new Array(V).fill(false);      // This will store all the connected components     let res = [];      // Iterate through all nodes     for (let i = 0; i < V; i++) {                  // If the node has not been visited, it's a new component         if (!vis[i]) {             let component = [];              // Perform DFS to collect all nodes in this component             dfs(i, adj, vis, component);              // Add the component to the result list             res.push(component);         }     }      return res; }  // Driver Code  let V = 5;  // Edge list representing the undirected graph as 2D array let edges = [     [0, 1],     [1, 2],     [3, 4] ];  // Get all connected components using the countComponents function let components = getComponents(V, edges);  // Print each connected component components.forEach(component => {     console.log(component.join(" ")); }); 

Output
0 1 2  3 4  

Time Complexity: O(V + E) where V is the number of vertices and E is the number of edges.
Auxiliary Space: O(V + E)

Approach 2: Using Disjoint Set Union (DSU)

The idea to solve the problem using DSU (Disjoint Set Union) is to initially declare all the nodes as individual subsets and then visit them. When a new unvisited node is encountered, unite it with the underlying subset. In this manner, a single component will be visited in each traversal

Step by Step implementation:

  • Declare an array arr[] of size V, where V is the total number of nodes in the graph.
  • The value at each index i of the array represents the parent of the node i.
  • At the beginning, each node is its own parent. This is the base state where each node is considered an individual subset.
  • Perform Union Operation:
    • When nodes are united, change the parent of one node to the other, ensuring that the sets are merged properly.
    • Each time two nodes are united, their parents are updated accordingly to reflect the new structure of the set.
  • Traverse the Nodes:
    • Go through each node from 0 to V-1.
    • If a node is its own parent (i.e., it is a representative of a set), perform the DSU (find and union) operation starting from that node.
  • Store the result of every component and return it.
C++
#include <bits/stdc++.h> using namespace std;  // Function to find the root parent of a node with path compression int findParent(vector<int>& parent, int x) {     if (parent[x] == x)         return x;     return parent[x] = findParent(parent, parent[x]); }  // Function to unite two subsets void unionSets(vector<int>& parent, int x, int y) {     int px = findParent(parent, x);     int py = findParent(parent, y);     if (px != py) {         parent[px] = py;     } }  // Function to find all connected components using DSU vector<vector<int>> getComponents(int V, vector<vector<int>>& edges) {          // Initialize each node as its own parent     vector<int> parent(V);     for (int i = 0; i < V; i++) {         parent[i] = i;     }      // Union sets using edge list     for (auto& edge : edges) {         unionSets(parent, edge[0], edge[1]);     }      // Apply path compression for all nodes     for (int i = 0; i < V; i++) {         parent[i] = findParent(parent, i);     }      // Group nodes by their root parent     unordered_map<int, vector<int>> resMap;     for (int i = 0; i < V; i++) {         resMap[parent[i]].push_back(i);     }      // Collect all components into a result vector     vector<vector<int>> res;     for (auto& entry : resMap) {         res.push_back(entry.second);     }      return res; }  int main() {     int V = 5;      // Edge list as vector of vectors     vector<vector<int>> edges = {         {0, 1},         {1, 2},         {3, 4}     };      // Find connected components using DSU     vector<vector<int>> res = getComponents(V, edges);          for (const auto& comp : res) {         for (int node : comp) {             cout << node << " ";         }         cout << endl;     }      return 0; } 
Java
import java.util.*;  class GfG {      // Function to find the root parent of a node with path compression      static int findParent(ArrayList<Integer> parent, int x) {         if (parent.get(x) == x)             return x;         parent.set(x, findParent(parent, parent.get(x)));          return parent.get(x);     }      // Function to unite two subsets     static void unionSets(ArrayList<Integer> parent, int x, int y) {         int px = findParent(parent, x);         int py = findParent(parent, y);         if (px != py) {             parent.set(px, py);          }     }      // Function to find all connected components using DSU     static ArrayList<ArrayList<Integer>> getComponents(int V, int[][] edges) {                  // Initialize each node as its own parent         ArrayList<Integer> parent = new ArrayList<>();         for (int i = 0; i < V; i++) {             parent.add(i);         }          // Union sets using edge list         for (int[] edge : edges) {             unionSets(parent, edge[0], edge[1]);         }          // Apply path compression for all nodes         for (int i = 0; i < V; i++) {             parent.set(i, findParent(parent, i));         }          // Group nodes by their root parent         Map<Integer, ArrayList<Integer>> resMap = new HashMap<>();         for (int i = 0; i < V; i++) {             resMap.putIfAbsent(parent.get(i), new ArrayList<>());             resMap.get(parent.get(i)).add(i);         }          // Collect all components into a result list         ArrayList<ArrayList<Integer>> res = new ArrayList<>();         for (Map.Entry<Integer, ArrayList<Integer>> entry : resMap.entrySet()) {             res.add(entry.getValue());         }          return res;     }      public static void main(String[] args) {         int V = 5;          // Edge list as 2D array         int[][] edges = {             {0, 1},             {1, 2},             {3, 4}         };          // Find connected components using DSU         ArrayList<ArrayList<Integer>> res = getComponents(V, edges);          // Print the connected components         for (ArrayList<Integer> comp : res) {             for (int node : comp) {                 System.out.print(node + " ");             }             System.out.println();         }     } } 
Python
# Function to find the root parent of a node with path compression def findParent(parent, x):     if parent[x] == x:         return x              # Path compression     parent[x] = findParent(parent, parent[x])       return parent[x]  # Function to unite two subsets def unionSets(parent, x, y):     px = findParent(parent, x)     py = findParent(parent, y)     if px != py:                  # Union operation         parent[px] = py    def getComponents(V, edges):          # Initialize each node as its own parent     parent = [i for i in range(V)]      # Union sets using the edge list     for edge in edges:         unionSets(parent, edge[0], edge[1])      # Apply path compression for all nodes     for i in range(V):         parent[i] = findParent(parent, i)      # Group nodes by their root parent     resMap = {}     for i in range(V):         root = parent[i]         if root not in resMap:             resMap[root] = []         resMap[root].append(i)      # Collect all components into a result list     res = list(resMap.values())      return res  if __name__ == "__main__":     V = 5      # Edge list as 2D array (list of lists)     edges = [         [0, 1],         [1, 2],         [3, 4]     ]      # Find connected components using DSU     res = getComponents(V, edges)      # Print connected components     for comp in res:         print(" ".join(map(str, comp))) 
C#
using System; using System.Collections.Generic;  class GfG {     // Function to find the root parent of a node with path compression     public static int findParent(List<int> parent, int x) {         if (parent[x] == x)             return x;                      // Path compression         parent[x] = findParent(parent, parent[x]);          return parent[x];     }      // Function to unite two subsets     public static void unionSets(List<int> parent, int x, int y) {         int px = findParent(parent, x);         int py = findParent(parent, y);         if (px != py) {             // Union operation             parent[px] = py;          }     }      // Function to find all connected components using DSU     public static List<List<int>> getComponents(int V, int[,] edges) {                  // Initialize each node as its own parent         List<int> parent = new List<int>(V);         for (int i = 0; i < V; i++) {             parent.Add(i);         }          // Union sets using the edge list         for (int i = 0; i < edges.GetLength(0); i++) {             unionSets(parent, edges[i, 0], edges[i, 1]);         }          // Apply path compression for all nodes         for (int i = 0; i < V; i++) {             parent[i] = findParent(parent, i);         }          // Group nodes by their root parent         Dictionary<int, List<int>> resMap = new Dictionary<int, List<int>>();         for (int i = 0; i < V; i++) {             int root = parent[i];             if (!resMap.ContainsKey(root)) {                 resMap[root] = new List<int>();             }             resMap[root].Add(i);         }          // Collect all components into a result list         List<List<int>> res = new List<List<int>>();         foreach (var entry in resMap) {             res.Add(entry.Value);         }          return res;     }      static void Main(string[] args) {         int V = 5;          // Edge list as a 2D array         int[,] edges = {             {0, 1},             {1, 2},             {3, 4}         };          // Find connected components using DSU         List<List<int>> res = getComponents(V, edges);          // Print connected components         foreach (var comp in res) {             foreach (int node in comp) {                 Console.Write(node + " ");             }             Console.WriteLine();         }     } } 
JavaScript
// Function to find the root parent of a node with path compression function findParent(parent, x) {     if (parent[x] === x)         return x;              // Path compression     parent[x] = findParent(parent, parent[x]);      return parent[x]; }  // Function to unite two subsets function unionSets(parent, x, y) {     let px = findParent(parent, x);     let py = findParent(parent, y);     if (px !== py) {                   // Union operation         parent[px] = py;     } }  function getComponents(V, edges) {          // Initialize each node as its own parent     let parent = [];     for (let i = 0; i < V; i++) {         parent[i] = i;     }      // Union sets using the edge list     for (let i = 0; i < edges.length; i++) {         unionSets(parent, edges[i][0], edges[i][1]);     }      // Apply path compression for all nodes     for (let i = 0; i < V; i++) {         parent[i] = findParent(parent, i);     }      // Group nodes by their root parent     let resMap = {};     for (let i = 0; i < V; i++) {         let root = parent[i];         if (!(root in resMap)) {             resMap[root] = [];         }         resMap[root].push(i);     }      // Collect all components into a result array     let res = [];     for (let key in resMap) {         res.push(resMap[key]);     }      return res; }  // Driver code let V = 5;  // Edge list as 2D array let edges = [     [0, 1],     [1, 2],     [3, 4] ];  // Find connected components using DSU let res = getComponents(V, edges);  // Print connected components for (let i = 0; i < res.length; i++) {     console.log(res[i].join(' ')); } 

Output
3 4  0 1 2  

Time Complexity: O(V+E)
Auxiliary Space: O(V)


Next Article
Connected Components in an Undirected Graph

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Article Tags :
  • Graph
  • DSA
  • BFS
  • DFS
  • graph-connectivity
Practice Tags :
  • BFS
  • DFS
  • Graph

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