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C Program To Print Hollow Pyramid Patterns
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C Program To Print Continuous Character Pyramid Pattern

Last Updated : 22 Sep, 2022
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There are 2 ways to print continuous character patterns in C i.e:

  1. Using for loop
  2. Using while loop

Input: 

rows = 5

Output:  

A  B C  D E F  G H I J  K L M N O

1. Using for loop

Approach 1: Using Character

  • Assign any character to one variable for the printing pattern. 
  • The first for loop is used to iterate the number of rows.
  • The second for loop is used to repeat the number of columns. 
  • Then print the character based on the number of columns and increment the character value at each column to print a continuous character pattern.

Below is the C program to print continuous character patterns using character using for loop: 

C
// C program to print continuous // character pattern using character  #include <stdio.h> int main() {     int i, j;      // Number of rows     int rows = 3;      // Taking first character of alphabet     // which is useful to print pattern     char character = 'A';      // This loop is used to identify     // number rows     for (i = 0; i < rows; i++) {                // This for loop is used to         // identify number of columns         // based on the rows         for (j = 0; j <= i; j++) {                        // Printing character to get             // the required pattern             printf("%c ", character);              // Incrementing character value so             // that it will print the next character             character++;         }         printf("\n");     }     return 0; } 

Output
A  B C  D E F 

Time complexity: O(R*R) where R is the given number of rows.
Auxiliary space: O(1), as constant space is being used.

Approach 2:  Converting a given number into a character

  • Assign any number to one variable for the printing pattern. 
  • The first for loop is used to iterate the number of rows.
  • The second for loop is used to repeat the number of columns. 
  • After entering into the loop convert the given number into character to print the required pattern based on the number of columns and increment the character value at each column to print a continuous character pattern.

Below is the C program to print continuous character patterns by converting numbers into a character:

C
// C program to print continuous // character pattern by converting // number in to character #include <stdio.h>  // Driver code int main() {     int i, j;      // Number of rows     int rows = 5;      // Given a number     int number = 65;      // This loop is used to identify     // number of rows     for (i = 0; i < rows; i++) {                // This loop is used to identify number         // of columns based on the rows         for (j = 0; j <= i; j++) {                        // Converting number in to character             char character = (char)(number);              // Printing character to get the             // required pattern             printf("%c ", character);              // Incrementing number value so             // that it will print the next             // character             number++;         }         printf("\n");     }     return 0; } 

Output
A  B C  D E F  G H I J  K L M N O 

Time complexity: O(R*R) where R is the given number of rows.
Auxiliary space: O(1), as constant space is being used.

2. Using while loop:

Approach 1: Using character

The while loops check the condition until the condition is false. If the condition is true then enter into a loop and execute the statements. Below is the C program to print continuous character patterns using character:

C
// C program to print the continuous // character pattern using while loop #include <stdio.h>  int main() {     int i = 1, j = 0;      // Number of rows     int rows = 5;      // Given a character     char character = 'A';      while (i <= rows) {         while (j <= i - 1) {                        // Printing character to get             // the required pattern             printf("%c ", character);             j++;              // Incrementing character value             // so that it will print the next             // character             character++;         }         printf("\n");          j = 0;         i++;     }     return 0; } 

Output
A  B C  D E F  G H I J  K L M N O 

Time complexity: O(R*R) where R is the given number of rows.
Auxiliary space: O(1), as constant space is being used.

Approach 2: Converting a given number into a character

Below is the C program to print a continuous character pattern by converting a given number into a character using a while loop:

C
// C program to print continuous // character pattern by converting // number in to character #include <stdio.h>  int main() {     int i = 1, j = 0;      // Number of rows     int rows = 5;      // Given a number     int number = 65;      while (i <= rows) {         while (j <= i - 1) {             // Converting number in to character             char character = (char)(number);              // Printing character to get the             // required pattern             printf("%c ", character);             j++;              // Incrementing number value so             // that it will print the next             // character             number++;         }         printf("\n");          j = 0;         i++;     }     return 0; } 

Output
A  B C  D E F  G H I J  K L M N O 

Time complexity: O(R*R) where R is the given number of rows.
Auxiliary space: O(1), as constant space is being used.


Next Article
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ksrikanth0498
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Article Tags :
  • C Programs
  • C Language
  • C Pattern Programs

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